The length of rectangular plate is 20.0 cm as measured by a meter scale. its width is measured by vernier calliper as 2.00 cm. the least count of vernier scale and meter scale are 0.01 cm and 0.1 cm respectively. the maximum possible error in area measurement is

• Physics is a quantitative science, based on the measurement of physical quantities. Certain physical quantities have been chosen as fundamental or base quantities (such as length, mass, time, electric current, thermodynamic temperature, amount of substance, and luminous intensity). • Each base quantity is defined in terms of a certain basic, arbitrarily chosen but properly standardized reference standard called unit (such as meter, kilogram, second, ampere, kelvin, mole, and candela). The units for the fundamental or base quantities are called fundamental or base units. • Other physical quantities, derived from the base quantities, can be expressed as acombination of the base units and are called derived units. A complete set of units, both fundamental and derived, is called a system of units. • The International System of Units (SI) based on seven base units is at the present aninternationally accepted unit system and is widely used throughout the world. • The SI units are used in all physical measurements, for both the base quantities and the derived quantities obtained from them. Certain derived units are expressed using SI units with special names (such as joule, newton, watt, etc). • The SI units have well-defined and internationally accepted unit symbols (such as m for meter, kg for kilogram, s for a second, A for ampere, N for newton, etc.). • Physical measurements are usually expressed for small and large quantities in scientific notation, with powers of 10. Scie...

The length of rectangular plate is 20.0 cm as measured by a meter scale. Its width is measured by vernier calliper as 2.00 cm. The least count of vernier scale and meter scale are 0.01 cm and 0.1 cm respectively. The maximum possible error in area measurement is • 0.2 cm 2 • 0.6 cm 2 • 0.3 cm 2 • 0.4 cm 2 The length of rectangular plate is 20.0 cm as measured by a meter scale. Its width is measured by vernier calliper as 2.00 cm. The least count of vernier scale and meter scale are 0.01 cm and 0.1 cm respectively. The maximum possible error in area measurement is Updated On Nov 27, 2022 Topic Mechanics Subject Physics Class Class 11 Answer Type Video solution: 2 Upvotes 246 Avg. Video Duration 15 min

Question Updated on: 13/06/2023 The length of a rectangular plate is measured by a meter scale and is found to be 10.0 c m. Its width is measured by vernier callipers as 1.00 c m. The least count of the meter scale and vernier calipers are 0.1 c m and 0.01 c m respectively. Maximum permissibe error in area measurement is. question is the length of a rectangular plate is measured by a metre scale and is found to be 10 cm if b is measured by vernier calipers has won the least count of the metre scale and when you calipers are 0.1 and 4.0 respectively maximum permissible error in the area measurement is given options point 2.1.30 admin in the options that is a b c and d so find the error in the area we have area given as product of length into B ok so by differentiating we can get the error formula that will be dealt in student Alpha Plus printer w by w w width ok so now to find the error in the area percentage we will have this will be close to delta H and Delta w h o w n 200% this will be caused you doing the values will have digital 0.1 CM divided by the value of 10 cm does Delta WS 0.011 and 200% from here we can get the value as point 01.01 in to 100% sure this will be overall 0.02% ok now to find the error permissible error Delta a Udit I will be Kuchh To a into 0.02% show the value of area a would be equal to find the value of a from here so length 10 cm into centimetre so area a would-be 10 square foot in the value of a year 10 into 0.02 from here will be get the erro...

In a vernier calipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided in 10 parts. While measuring a length, the zero of the vernier lies just ahead of 1.8 cm mark and 4 t h division of vernier coincides with a main scale division. (a) Find the length (b) If zero of vernier calipers is -0.2 cm, what is the correct length? A vernier calipers having zero error is used to determine the thickness of a hollow tube. While measuring the outer and inner diameter main scale readings are found to be 8 cm and 7 cm respectively and the vernier scale readings are 9 and 8 divisions respectively. If the number of vernier scale divisions is 10 and one MSD = 1mm, determine the thickness of the tube .

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In a Searle's experiment, the diameter of the wire as measured by a screw gauge with least count 0.001 cm is 0.050 cm. The length, measured by a scale of least count 0.1 cm, is 110.0 cm. When a weight of 50 N is suspended from the wire, the extension is measured to be 0.125 cm by a micrometer of least count 0.001 cm. Find the maximum error in the measurement of Young's modulus of the material of the wire from these data. y = W / A × L / XWhere W is the weight suspended from the wire, A is the cross section area, L is the length and X is the extension in the wire.[IIT JEE 2004]A. 15.56 %B. 4.89 %C. 1.26 %D. 9.67 % In a Searle's experiment, the diameter of the wire as measured by a screw gauge with least count 0.001 cm is 0.050 cm. The length, measured by a scale of least count 0.1 cm, is 110.0 cm. When a weight of 50 N is suspended from the wire, the extension is measured to be 0.125 cm by a micrometer of least count 0.001 cm. Find the maximum error in the measurement of Young's modulus of the material of the wire from these data. y = W A × L X Where W is the weight suspended from the wire, A is the cross section area, L is the length and X is the extension in the wire. [IIT JEE 2004] Q. In a Searle's experiment, the diameter of the wire as measured by a screw gauge with least count 0.001 cm is 0.050 cm. The length, measured by a scale of least count 0.1 cm, is 110.0 cm. When a weight of 50 N is suspended from the wire, the extension is measured to be 0.125 cm by a microm...

Figure shows an experimental setup to find the value of an unknown resistance R, using a meter bridge. AB is uniform meter bridge wire of length L = 100 cm. When sliding jockey is at J (AJ = x), the galvanometer shows zero deflection. Length AJ is measured by a meter scale having least count of 1mm. In an experiment known resistance is taken as 20 s2, length was found to be (20.0 + 0.1)cm (A) Value of R = (5.00 0.03)2 (B) Value of R = (5.00 = 0.02) (C) To minimize fractional error the known resistance should be very close to Rx (D) Fractional error is minimum when x A resistance of 2 Ω is connected across one gap of a metre bridge (the length of the wire is 100 cm) and an unknown resistance greater than 2 Ω is connected across the other gap. When these resistances are interchanged, the balance point shifts by 20 cm . Neglecting any corrections, the unknown resistance is: The resistance of 2 Ω is connected across one gap of a meter-bridge (length of the wire is 100 cm) and an unknown resistance greater than 2 Ω is connected across the other gap. When the resistance are interchanged, the balance point shifts by 20cm. Neglecting any corrections, the unknown resistance is: (in Ω)

Size of rectangular sheet = 30 cm × 18 cm ∴ Length of sheet = 30 cm and breadth = 18 cm By folding length wise, Height = 18 cm and circumference = 30 cm ∴ R a d i u s = C i r c u m f e r e n c e 2 π = 30 2 π Volume = π r 2 h = π × 30 2 π × 30 2 π × 18 = 16200 4 π = 8100 2 π c m 3 In second case, By folding width wise, Height = 30 cm and circumference = 18 cm ∴ R a d i u s = C 2 π = 18 2 π Volume = π ( 18 2 π ) 2 × 30 = π × 18 2 π × 18 2 π × 30 = 2430 π c m 3 ∴ Ratio in their volumes = 8100 2 π : 2430 π = 5:3