The ratio of present ages of ravi and sanjay is 2 is to 3 is to 15

  1. The present age of Ravi and Meenu are in the ratio 5:7. After 4 years their ages will be in the ratio 3:4. Find their present ages.
  2. Quadratic Equation Questions & Answers
  3. Problems on Ages
  4. Age


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The present age of Ravi and Meenu are in the ratio 5:7. After 4 years their ages will be in the ratio 3:4. Find their present ages.

Finding their present ages: Let the present age of Ravi = 5 x years. Let the present age of Meenu = 7 x years. After 4 years, The age of Ravi = 5 x + 4 The age of Meenu = 7 x + 4 Ratio of age of Ravi and Meenu after 4 years, = 5 x + 4 7 x + 4 But, according to question, after 4 years their ages will be in the ratio 3 : 4 ∴ 5 x + 4 7 x + 4 = 3 4 ( 5 x + 4 ) × 4 = ( 7 x + 4 ) × 3 20 x + 16 = 21 x + 12 20 x - 21 x = 12 - 16 - x = - 4 x = 4 Hence, Ravi’s present age = 5 x = 5 × 4 = 20 years. Meenu’s present age = 7 x = 7 × 4 = 28 years.

Quadratic Equation Questions & Answers

Quadratic Equation Questions & Answers PDF Download. A quadratic equation is a part of the Quantitative Aptitude section. Candidates are you seeking to practice the multiple-choice questions based on this Quadratic equation often make an appearance in the SSC, Railways Exams, and other Competitive exams. It is one of the essential and highest-scoring topics which you can easily face in the banking exam Quadratic Equation- Part I Download Reasoning Questions with Answers Pdf Download Nov 2020 Current Affairs Pdf Directions (1 – 5): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer. • I. x² – 34x + 288 = 0 II.y² – 28y + 192 = 0 A. x > y B. x y B. x y B. x y B. x y B. x Quantity II B. Quantity I Quantity II B. Quantity I Quantity II B. Quantity I Quantity II B. Quantity I Quantity II B. Quantity I < Quantity II C. Quantity I ≥ Quantity II D. Quantity I ≤ Quantity II E. Quantity I = Quantity II or relation cannot be established Correct option is : B Solution: Work done by the two pipes in 1 hour = (1/12)+(1/18) = (15/108). Time taken by these pipes to fill the tank = (108/15)hrs = 7 hours 12 min. Due to leakage, time taken to fill the tank = 7 hours 12 min + 48 min = 8 hours Work done by two pipes and leak in 1 hour = 1/8. Work done by the leak in 1 hour =(15/108)-(1/8)=(1/72). Leak will empty the full cistern in 72 hours. Quadratic Equation Questions & Answers Latest police jobs 2020 Online Mock Tes...

Problems on Ages

• • • • Exercise Working methodology: In these problems, two persons initial ages will be given. and before or after several years, their ratio of the ages will be given. Multiply the ratio of their initial age by x or some variable and take them as their initial age. Now if final ratio has been given, equate this ratio with that ratio and find x. Or proceed according to the problem. 1. The present age of Gopal is 15 years. His age after 7 years is a. 20 b. 21 c. 22 d. 23 Explanation: $\begin$ The age of Jaya 5 years ago = $12$ years Current age of Jaya = $12 + 5 = 17$ years Jaya's age 3 years hence = $17 + 3 = 20$ years Show Explanation Show Answer 3. The difference between the ages of Latha and her father 7 years ago is 25 years. The difference between their ages after 10 years is : a. 20 years b. 25 years c. 35 years d. 45 years Explanation: The difference between two person's age doesn't change with progress of years. It is constant. So answer is $25$ years. Show Explanation Show Answer 4. The ratio of the ages of Meena and Meera is 4:3. The sum of their ages is 28 years. The ratio of their ages after 8 years will be : a. 4 : 3 b. 12 : 11 c. 7 : 4 d. 6 : 5 Explanation: Let Meena's age = $4x$ or Meera's age = $3x$. Then, $4x + 3x = 28$ $\Rightarrow x = 4$ Meena's age = $4 \times 4 = 16$ years Meera's age = $4 \times 3 = 12$ years After 8 years their ages $= 16 + 8 = 24$ and $12 + 8 = 20$. So ratio = $24 : 20$ = $6 : 5$ Show Explanation Show Answer 5.The ages of Ravi and...

Age

Ravi has three children: two daughters and one son. All were born on the same date in different years. The sum of the ages of the two daughters today is smaller than the age of the son today, but a year from now the sum of the ages of the daughters will equal the age of the son. Three years from today, the difference between the age of the son and the combined ages of the daughters will be • A. 1 The average runs scored by a cricketer is 42 innings, is 40. The difference between his maximum and minimum scores in an inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is 37. Calculate the maximum runs scored by him in an innings? • A. 125 Eight years ago, Pavi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ratio between the ages of her daughter and her son that time will be 7:6. If Pavi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter? • A. 15 years