The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9 atm and 6 atm respectively are connected. what is the final pressure in the two bulbs if the temperature remains constant?

  1. Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stop
  2. The stop cock connecting two bulbs of volume 5 litre and 10 litre cont
  3. Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure `P_(i)` and temperature `T_(1)` are connected through a narrow tube
  4. The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9 atm and 6 atm respectively are connected. What is the final pressure in the two bulbs if the temperature remains constant ?
  5. Solved the two bulbs of volume 5 ltr &10 ltr containing an
  6. The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9..
  7. Separation Chemistry [PDF] [4hu0c3t3ved0]
  8. Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stop
  9. The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9..
  10. Solved the two bulbs of volume 5 ltr &10 ltr containing an


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Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stop

Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stopcocks are opened. Assuming that temperature remain constant. (Neglect the volume of capollary tubing connecting bulbs) A. 440 torr B. 200 torr C. 360 torr D. 320 torr Correct Answer - A After all stopcocks are opened, gases move unit partial pressure becomes same in all bulbs For `O_(2)` gas `P_(1) V_(1) = P_(2) V_(2)` `P_(1) = 300` torr, `P_(2)` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `300 xx 1 = P_(2) xx 2.5` `P_(2) = 120` torr For He gas `P_(1) V_(1) = P_(2)V_(2)` `P_(1) = 600` torr, `P_(2) =` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `600 xx 1 = P_(2) xx 2.5` `P_(2) = 240` torr For `N_(2)` gas `P_(1)V_(1) = P_(2)V_(2)` `P_(1) = 400` torr, `P_(2) =` ? `V_(1) = 0.5` litre, `V_(2) = 2.5` litre `400 xx (1)/(2) = P_(2) xx (5)/(2)` `P_(2) = 80` torr Pressure of system `= P_(O_(2)) + P_(N_(2)) + P_(He)` `= 120 + 80 + 240` `= 440` torr

The stop cock connecting two bulbs of volume 5 litre and 10 litre cont

• Course • NCERT • Class 12 • Class 11 • Class 10 • Class 9 • Class 8 • Class 7 • Class 6 • IIT JEE • Exam • JEE MAINS • JEE ADVANCED • X BOARDS • XII BOARDS • NEET • Neet Previous Year (Year Wise) • Physics Previous Year • Chemistry Previous Year • Biology Previous Year • Neet All Sample Papers • Sample Papers Biology • Sample Papers Physics • Sample Papers Chemistry • Download PDF's • Class 12 • Class 11 • Class 10 • Class 9 • Class 8 • Class 7 • Class 6 • Exam Corner • Online Class • Quiz • Ask Doubt on Whatsapp • Search Doubtnut • English Dictionary • Toppers Talk • Blog • Download • Get App A bulb 'X' of unknown volume containing a gas at one atmospheric pressure is connected to an evacuated bulb of 0.5 litre capacity through a stop -cock. On opening the stop-cock, the pressure in the whole system after some time was found to have a constant value of 570 mm at the same temperature. What is the volume of the bulb X ? Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep, NEET preparation and CBSE, UP Board, Bihar Board, Rajasthan Board, MP Board, Telangana Board etc NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year papers, NEET ...

Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure `P_(i)` and temperature `T_(1)` are connected through a narrow tube

Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure `P_(i)` and temperature `T_(1)` are connected through a narrow tube of negligible volume as shown in the figure below. The temperature of one of the bulbs is then raised to `T_(2)`. The final pressure `P_(f)` is : A. `p_(i) ((T_(1)T_(2))/(T_(1) + T_(2)))` B. `2p_(i) ((T_(1))/(T_(1) + T_(2)))` C. `2 P_(i) ((T_(2))/(T_(1) + T_(2)))` D. `2 p_(i) ((T_(1) T_(2))/(T_(1) + T_(2)))` Categories • • (31.9k) • (8.8k) • (764k) • (261k) • (257k) • (218k) • (248k) • (2.9k) • (5.2k) • (664) • (121k) • (72.1k) • (3.8k) • (19.6k) • (1.4k) • (14.2k) • (12.5k) • (9.3k) • (7.7k) • (3.9k) • (6.7k) • (63.8k) • (26.6k) • (23.7k) • (14.6k) • (25.7k) • (530) • (84) • (766) • (49.1k) • (63.8k) • (1.8k) • (59.3k) • (24.5k)

The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9 atm and 6 atm respectively are connected. What is the final pressure in the two bulbs if the temperature remains constant ?

Only gases remains after 1 5 . 0 g of carbon is treated with 2 0 L of air at 3 8 0 K and 8 . 2 1 a t m pressure. (Assume 1 9 % by volume oxygen, 8 0 % nitrogen, 1 % carbon dioxide). Determine the amount of heat evolved (in k c a l) under constant pressure. Enthalpies of formation of C O 2 ​ ( g ) and C O ( g ) are − 9 6 . 0 and − 2 6 . 0 k c a l / m o l, respectively.

Solved the two bulbs of volume 5 ltr &10 ltr containing an

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:the two bulbs of volume 5 ltr &10 ltr containing an idealgas at 9 atm & 6 atm respectively is opened . what is the finalpressure in the 2 bulbs if the temp. remains constant?15 atm7atm12atm21atm

The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9..

• They are quite soft and can be cut easily. Sodium metal can be easily cut using a knife. • They are light coloured and are mostly silvery white in appearance. • They have low density because of the large atomic sizes. The density increases down the group from Li to Cs. The only exception to this is K, which has lower density than Na. • The metallic bonding present in alkali metals is quite weak. Therefore, they have low melting and boiling points. • Alkali metals and their salts impart a characteristic colour to flames. This is because the heat from the flame excites the electron present in the outermost orbital to a high energy level. When this excited electron reverts back to the ground state, it emits excess energy as radiation that falls in the visible region. • They also display photoelectric effect. When metals such as C ss and K are irradiated with light, they lose electrons. The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9 atm and 6 atm respectively are connected. What is the final pressure in the two bulbs if the temperature remains constant? Updated On Dec 1, 2022 Topic s-Block Subject Chemistry Class Class 11 Answer Type Video solution: 1 Upvotes 79 Avg. Video Duration 17 min

Separation Chemistry [PDF] [4hu0c3t3ved0]

This page intentionally left blank Copyright © 2004, New Age International (P) Ltd., Publishers Published by New Age International (P) Ltd., Publishers All rights reserved. No part of this ebook may be reproduced in any form, by photostat, microfilm, xerography, or any other means, or incorporated into any information retrieval system, electronic or mechanical, without the written permission of the publisher. All inquiries should be emailed to ISBN (13) : 978-81-224-2531-4 PUBLISHING FOR ONE WORLD NEW AGE INTERNATIONAL (P) LIMITED, PUBLISHERS 4835/24, Ansari Road, Daryaganj, New Delhi - 110002 Visit us at www.newagepublishers.com To the Memory of my Parents with affection and reverence This page intentionally left blank Contents Preface vii 1. Introduction 1 PART I Traditional Methods of Separation and Purification 2. Methods of Everyday Use 11 PART II Chemical Methods of Separation and Purification 3. Chemical Methods of Separation and Purification 57 PART III Chromatographic Techniques 4. Methods Involving Two Immiscible Phases of which One Phase is Stationary and the other One Mobile 69 5. Adsorption Column Chromatography [Liquid-Solid Chromatography] 79 6. Partition Column Chromatography [Liquid-Liquid Chromatography] 90 7. Relationship of Theory to Practice of Liquid Chromatography 113 8. Ion-Exchange Chromatography 139 9. Gel Chromatography 164 10. High Performance Liquid Chromatography (HPLC) 171 11. Paper Chromatography 240 12. Thin-layer Chromatography 251 13. Gas...

Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stop

Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stopcocks are opened. Assuming that temperature remain constant. (Neglect the volume of capollary tubing connecting bulbs) A. 440 torr B. 200 torr C. 360 torr D. 320 torr Correct Answer - A After all stopcocks are opened, gases move unit partial pressure becomes same in all bulbs For `O_(2)` gas `P_(1) V_(1) = P_(2) V_(2)` `P_(1) = 300` torr, `P_(2)` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `300 xx 1 = P_(2) xx 2.5` `P_(2) = 120` torr For He gas `P_(1) V_(1) = P_(2)V_(2)` `P_(1) = 600` torr, `P_(2) =` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `600 xx 1 = P_(2) xx 2.5` `P_(2) = 240` torr For `N_(2)` gas `P_(1)V_(1) = P_(2)V_(2)` `P_(1) = 400` torr, `P_(2) =` ? `V_(1) = 0.5` litre, `V_(2) = 2.5` litre `400 xx (1)/(2) = P_(2) xx (5)/(2)` `P_(2) = 80` torr Pressure of system `= P_(O_(2)) + P_(N_(2)) + P_(He)` `= 120 + 80 + 240` `= 440` torr Categories • • (31.9k) • (8.8k) • (764k) • (261k) • (257k) • (218k) • (248k) • (2.9k) • (5.2k) • (664) • (121k) • (72.1k) • (3.8k) • (19.6k) • (1.4k) • (14.2k) • (12.5k) • (9.3k) • (7.7k) • (3.9k) • (6.7k) • (63.8k) • (26.6k) • (23.7k) • (14.6k) • (25.7k) • (530) • (84) • (766) • (49.1k) • (63.8k) • (1.8k) • (59.3k) • (24.5k)

The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9..

Views: 5,634 α-maltose can be hydrolysed to glucose according to the following reaction. α − C 12 ​ H 22 ​ O 11 ​ ( a q ) + H 2 ​ O ( l ) → 2 C 6 ​ H 12 ​ O 6 ​ ( a q ) The standard enthalpy of formation of H 2 ​ O ( l ), C 6 ​ H 12 ​ O 6 ​ ( a q ) and α − C 12 ​ H 22 ​ O 11 ​ ( a q ) are − 285, − 1263 and − 2238 kJ / mol, respectively. Which of the following statement(s) is/are true? • The hydrolysis reaction is exothermic. • Heat liberated in combustion of 1.0 mole of α-maltose is smaller than the heat liberated in combustion of 2.0 mole of glucose neglecting the effect of hydration. • Increase in temperature will increase the degree of hydrolysis of α-maltose. • Enthalpy of reaction will remain the same even if solid α-maltose is taken in the reaction. The two bulbs of volume 5 litre and 10 litre containing an ideal gas at 9 atm and 6 atm respectively are connected. What is the final pressure in the two bulbs if the temperature remains constant? Updated On Dec 1, 2022 Topic s-Block Subject Chemistry Class Class 11 Answer Type Video solution: 1 Upvotes 79 Avg. Video Duration 17 min

Solved the two bulbs of volume 5 ltr &10 ltr containing an

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:the two bulbs of volume 5 ltr &10 ltr containing an idealgas at 9 atm & 6 atm respectively is opened . what is the finalpressure in the 2 bulbs if the temp. remains constant?15 atm7atm12atm21atm

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