Treating phenol with chloroform in presence of aqueous naoh

You are about to begin Topic 5, Preparation, Purification, and Quantitation. In this topic you’ll learn about DNA extraction & purification and the Quantitaion of DNA & RNA. You will start by clicking on the next button at the bottom of the page to being reviewing the basics elements of laboratory safety. Objectives Upon completion of this module topic, you will: • be able to isolate plasmid DNA by harvesting bacterial cells through centrifugation. • be able to lyse the bacterial cells and extract and purify the plasmid DNA using and following the protocol described in a Qiagen Miniprep or Maxiprep Kit depending upon the amount of plasmid product desired. You should be able to also explain the buffers and reactions that make up the Qiagen kits. • be able to quantitate the concentration of DNA that has been purified through the Qiagen kit protocol using an Ultraviolet spectrophotometer. • be able to explain which wavelengths are used to determine concentration and quality. Part a DNA Extraction & Purification This is Part A, DNA Extraction & Purification, under the module topic, Preparation, Purification, and Quantitation of DNA & RNA. This topic part has two sections: Content Tutorial and Activities. Content Tutorial *Note: The tutorial sections for this module subset offer a variation from the common content-based scheme you have been exploring in the previous Nucleic Acid module subsets. This subset will provide you with the procedural information (protocols) you will ne...

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Hint: To find the products of the given reactions. We must know the type of reaction which is taking place. The type of reaction which is taking place is electrophilic substitution reaction, nitration, reimer-tiemann reaction. Complete answer: $ A) $ Oxidation of propan- $ 1 $ -ol with alkaline $ KMn $ is a strong oxidizing agent.so, it will oxidise propan- $ 1 $ -ol to propanoic acid. $ B) $ Bromine in $ C $ with phenol. This reaction is an electrophilic substitution reaction. In an electrophilic replacement reaction, a couple of π-bonded electrons first attack an electrophile - generally a carbocation species - and a proton is then disconnected from a neighboring carbon to restore the double bond, either in the first position or with isomerization. In this reaction two products will form first is $ o - $ substituted and $ p - $ substituted. $ C) $ Dilute $ HN $ with phenol. This is a nitration reaction.Nitro group into a natural compound. The term additionally is applied mistakenly to the diverse cycle of shaping nitrate esters among alcohols and nitric acid. The distinction between the subsequent subatomic designs of nitro mixtures and nitrates is that the nitrogen molecule in nitro compounds is straightforwardly attached to a non-oxygen particle, while in nitrate esters, the nitrogen is clung to an oxygen particle that thusly as a rule is clung to a carbon molecule. IN this the product will form first is $ o - $ substituted and $ p - $ substituted. $ D) $ Treating phen...

The correct option is C electrophilic substitution reaction When phenol gets converted to salicylaldehyde in the presence of C H C l 3 + A q . N a O H followed by hydrolysis, the reaction is known as Reimer-Tiemann reaction. It is an electrophilic substitution reaction, reaction intermediate dichloro carbene is formed and acts as an electrophile. Hence, the correct answer is option (c).

• When phenol in chloroform is treated with aqueous NaOH , the Riemann Tiemann reaction takes place. It gives salicylaldehyde as a major product. the reaction is given below- • The major product P is salicylaldehyde. Its molecular formula is C 7 H 6 O 2 . The molecular mass of salicylaldehyde is 122 g • Calculation - mass % of carbon in a compound = molar mass of carbon in compoud molecular mass of compound × 100 • Mass % of carbon in salicylaldehyde - 7 × 12 122 × 100 = 68 . 85 ≈ 69 % So, the mass % of carbon in P is 69 % .

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