Two trains start from a & b and travel towards each other at speed of 40 km/hr and 60 km/hr respectively. after crossing each other b had to travel another 120 km to reach origin city of a. then find the distance between a and b.

Correct Option: A Let the trains meet after t hours Then, 21t – 16t = 60 ⇒ 5t = 60 ⇒ t = 12 hours ∴ Distance between A and B = (16 + 21) × 12 = 37 × 12 = 444 miles Second Method : Here, a = 21, b = 16, d = 60 Distance between A and B = a + b × d a − b = 21 + 16 × 60 21 − 16 = 37 × 60 5 = 37 × 12 = 444 miles

The correct option is D 624 Let the two trains be P and Q, Then, speed ratio = P : Q = 36 : 42 = 6x : 7x Then ratio of distance covered before the meet = 6x : 7x and difference of distance covered = 7x - 6x = x = 48. So, distance between A and B = 7x + 6x = 13x = 13 × 48 = 624 k m . Alternate Approach: Let the distance between A and B be x km. Speed of two trains are 36 km/h and 42 km/h. Relative speed = 78 km/h Time taken = x 78 h Now, first train has travelled x 78 × 36 = 36 x 78 k m Second train has travelled 42 x 78 k m . Hence, 42 x 78 − 36 x 78 = 48 or 6 x 78 = 48 Hence, x = 78 × 8 = 624 k m

This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question:1) Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z takes 25 hours. If the city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to, how far will each train travel in total to reach its destination? Which of the following rational equations best 1) Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z takes 25 hours. If the city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to, how far will each train travel in total to reach its destination? Which of the following rational equations best models this situation? T X - 400 25 20 T + 400 20 25 О x + 400 = 20 25 O r 11 x + 400 20 25 2 O 400 20 25 Previous question Next question

I cant seem to solve this problem. A train leaves point A at 5 am and reaches point B at 9 am. Another train leaves point B at 7 am and reaches point A at 10:30 am.When will the two trains meet ? Ans 56 min Here is where i get stuck. I know that when the two trains meets the sum of their distances travelled will be equal to the total sum , here is what I know so far Time traveled from A to B by Train 1 = 4 hours Time traveled from B to A by Train 2 = 7/2 hours Now if S=Total distance from A To B and t is the time they meet each other then $$\text $$ Now is there any way i could get the value of S so that i could use it here. ?? We do not need $S$. The speed of the train starting from $A$ is $S/4$ while the speed of the train starting from $B$ is $S/(7/2) = 2S/7$. Let the trains meet at time $t$ where $t$ is measured in measured in hours and is the time taken by the train from $B$ when the two trains meet. Note that when train $B$ is about to start train $A$ would have already covered half its distance i.e. a distance of $S/2$. Hence, the distance traveled by train $A$ when they meet is $\dfrac7$$ Can you solve for $t$ now? (Note that $t$ is in hours. You need to multiply by $60$ to get the answer in minutes.) Since both trains move toward each other when remaining half of a space, then the general meeting equation in t is: $$v_)$$ Q.E.D. Let $d$ be the distance between $A$ and $B$, and assume the trains travel at constant speed. Let $a(t)$ denote the position of the train ...