2.2 calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

  1. 2.2. Calculate the mole fraction of benzene in solution containing 30% by..
  2. calculate the mole fraction of benzene
  3. (PDF) Coulson richardson's chemical engineering volume 2 solution manual soln
  4. NCERT Solutions class 12 Chemistry Solutions In text question
  5. Calculate the mole fraction of benzene in a solution containing 30 % by mass of carbon tetrachloride


Download: 2.2 calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.
Size: 71.75 MB

2.2. Calculate the mole fraction of benzene in solution containing 30% by..

2.2. Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride. Ans: 30% by mass of C 6 ​ H 6 ​ in CCl 4 ​ => 30 g C 6 ​ H 6 ​ in 100 g solution ∴ no. of moles of C 6 ​ H 6 ​ , ( n C 6 ​ h 6 ​ ) = 30/78 = 0.385 (molar mass of C 6 ​ H 6 ​ = 78 g ) no. of moles of CCl 4 ​ ( n CCl 4 ​ ​ ) = 154 70 ​ = 0.455 x C 6 ​ H 6 ​ ​ = n C 6 ​ H 6 ​ ​ + n CCl 4 ​ ​ n C 6 ​ H 6 ​ ​ ​ = 0.385 + 0.455 0.385 ​ = 0.84 0.385 ​ = 0.458 x CCl 4 ​ ​ = 1 − 0.458 = 0.542 ​ 2.2. Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride. Ans: 30% by mass of C 6 ​ H 6 ​ in CCl 4 ​ => 30 g C 6 ​ H 6 ​ in 100 g solution ∴ no. of moles of C 6 ​ H 6 ​ , ( n C 6 ​ h 6 ​ ) = 30/78 = 0.385 (molar mass of C 6 ​ H 6 ​ = 78 g ) no. of moles of CCl 4 ​ ( n CCl 4 ​ ​ ) = 154 70 ​ = 0.455 x C 6 ​ H 6 ​ ​ = n C 6 ​ H 6 ​ ​ + n CCl 4 ​ ​ n C 6 ​ H 6 ​ ​ ​ = 0.385 + 0.455 0.385 ​ = 0.84 0.385 ​ = 0.458 x CCl 4 ​ ​ = 1 − 0.458 = 0.542 ​ Updated On May 5, 2023 Topic Gases & Solutions Subject Chemistry Class Class 12 Answer Type Video solution: 1 Upvotes 117 Avg. Video Duration 6 min

calculate the mole fraction of benzene

Calculate the mole fraction of benzene in solution containing 30 Let the mass of solution be 100 gmMass of Benzene =30 gmMass of CCl 4=70 gmMoles of Benzene = 7830=0.385Moles of CCl 4= 15470=0.45 molesMole fraction (Benzene) = …Mole Fraction Formula: Meaning, Concept, Formula, Solved Examples - Toppr-guidesCalculate the mole fraction of ethylene glycol (C2H6O2) in a solution containing 20 - Toppr AskCalculate the mole fraction of a benzene - toluene liquid solution that is in equilibrium with a vap…Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solutio…• Calculate the mole fraction of benzene in a solution containing 30 … /cite> In the case of Benzene: Mass of benzene = 30 grams molar mass of benzene = 78 N u m b e r o f m o l e s = W e i g h t i n g r a m s M o l e c u l a r w e i g h t Nuer of moles of benzene = 30 … Calculate the mole fraction of benzene in solution containing 30 Answer Zigya App Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride. 897 Views Switch Flag Bookmark Calculate (a) molality (b) molarity and (c) mole fraction of KI if the density of 20% (mass/mass) aqueous KI is 1.202 g mL-1. 1010 Views Answer Company Careers Terms of Use Privacy Policy Sitemap Mole fraction, percentage by mass: Numerical problems - The … 2020129· To Find: Mole fraction of benzene =? Solution: Molecular mass of benzene (C 6 H 6) = 12 g x 6 + 1 g x 6 = 78 g mol -1 Molecular mass of carbon t...

(PDF) Coulson richardson's chemical engineering volume 2 solution manual soln

IN THE preface to the first edition of Chemical Engineering, Volume 4, we quoted the following paragraph written by Coulson and Richardson in their preface to the first edition of Chemical Engineering, Volume 1: We have introduced into each chapter a number of worked examples which we believe are essential to a proper understanding of the methods of treatment given in the text. It is very desirable for a student to understand a worked example before tackling fresh practical problems himself. Chemical Engineering problems require a numerical answer, and it is essential to become familiar with the different techniques so that the answer is obtained by systematic methods rather than by intuition.'

NCERT Solutions class 12 Chemistry Solutions In text question

Table of Contents • • • • NCERT Solutions class 12 Chemistry Solutions In text question Class 12 Chemistry book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Chemistry chapter wise NCERT solution for Chemistry part 1 and Chemistry part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free. Download NCERT Class 12 Chemistry Chapter-wise Solutions • 1 – The Solid State • 2 – Solutions • 3 – Electrochemistry • 4 – Chemical Kinetics • 5 – Surface Chemistry • 6 – General Principles and Processes of Isolation of Elements • 7 – The p-Block Elements • 8 – The d-and f-Blocks Elements • 9 – Coordination Compounds • 10 – Haloalkanes and Haloarenes • 11 – Alcohols, Phenols and Ethers • 12 – Aldehydes, Ketones and Carboxylic Acids • 13 – Amines • 14 – Biomolecules • 15 – Polymers • 16 – Chemistry in Everyday Life CHAPTER TWO SOLUTIONS • 2.1 Types of Solutions • 2.2 Expressing Concentration of Solutions • 2.3 Solubility • 2.4 Vapour Pressure of Liquid Solutions • 2.5 Ideal and Non-Ideal Solutions • 2.6 Colligative Properties and Determination of Molar Mass • 2.7 Abnormal Molar Masses NCERT Solutions class 12 Chemistry Solutions In text question 1. Calculate the mass percentage of benzene ( ) and carbon tetrachloride ( ) if 22 g of benzene is...

Calculate the mole fraction of benzene in a solution containing 30 % by mass of carbon tetrachloride

Let us consider that the mass of the solution is 100 grams In the case of Benzene: Mass of benzene = 30 grams molar mass of benzene = 78 N u m b e r o f m o l e s = W e i g h t i n g r a m s M o l e c u l a r w e i g h t Number of moles of benzene = 30 78 = 0.38 In the case of Carbon tetrachloride: mass of carbon tetrachloride = 70 molar mass of carbon tetrachloride = 154 N u m b e r o f m o l e s o f c a r b o n t e t r a c h l o r i d e = G i v e n m a s s o f c a r b o n t e t r a c h l o r i d e M o l e c u l a r m a s s o f c a r b o n t e t r a c h l o r i d e Number of moles of carbon tetrachloride = 70 154 = 0.45 Therefore, the total number of moles = 0.38+0.45 = 0.83 Now, M o l e f r a c t i o n o f b e n z e n e = N u m b e r o f m o l e s o f b e n z e n e N u m b e r o f m o l e s o f b e n z e n e + N u m b e r o f m o l e s o f c a r b o n t e t r a c h l o r i d e M o l e f r a c t i o n o f b e n z e n e = 0.38 0.38 + 0.45 = 0.461 Conclusion: Thus, the mole fraction of benzene is 0.461