An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. the initial and the final points of the path of the object lie on the same horizontal line. what is the work done by the force of gravity on the object?

  1. NCERT Solutions for Class 9 Science Chapter 11 Work and Energy
  2. An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?
  3. An object thrown at a certain angle to the ground moves in a curved pa
  4. An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path ob
  5. Question 2An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?
  6. An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?
  7. NCERT Solutions for Class 9 Science Chapter 11 Work and Energy
  8. Question 2An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?
  9. An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?
  10. An object thrown at a certain angle to the ground moves in a curved pa


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NCERT Solutions for Class 9 Science Chapter 11 Work and Energy

• NCERT Solutions Menu Toggle • NCERT Solutions for Class 12 • NCERT Solutions for Class 11 • NCERT Solutions for Class 10 • NCERT Solutions for Class 9 • NCERT Solutions for Class 8 • NCERT Solutions for Class 7 • NCERT Solutions for Class 6 • NCERT Books • TS Grewal Solutions • MCQ Questions Menu Toggle • NCERT MCQ These Work and Energy NCERT Solutions for Class 9 Science Chapter 11 Class 9 Scien ce Chapter 11 Work and Energy InText Questions and Answers Question 1. A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force (Fig. 11.3). Let us take it that the force acts on the object through the displacement. What is the work done in this case? Answer: When a force F acts on an object to displace it through a distance S in its direction, then the work done W on the body by the force is given by: Work done = Force x Displacement W = F × S Where, F = 7N S = 8m Therefore, work done, W = 7 × 8 = 56 Nm = 56 J Question 2. When do we say that work is done? Answer: Work is done whenever the given conditions are satisfied: • A force acts On the body. • There is a displacement of the body caused by the applied force along the direction of the applied force. Question 3. Write an expression for the work done when a force is acting on an object in the direction of its displacement. Answer: When a force F displaces a body through a distance S in the direction of the applied force, then the work done W on the body is given by the expression: Work don...

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

Work done by theforce of gravity on an object depends only on vertical displacement. Vertical displacement is given by the difference in the initial and final positions/heights of the object, which is zero. Work done by gravity is given by the expression, W= mg h Where, h= Vertical displacement = 0 W = mg × 0 = 0 J Therefore, the work done by gravity on the given object is zero joule.

An object thrown at a certain angle to the ground moves in a curved pa

Solution Work done by the force of gravity on an object depends only on vertical displacement vertical displacement is given by the difference in the initial and final portions/ heights of the objects, which is zero. Work done by gravity is given by the expression. w=mgh, where h = vrtical displacement = 0 w = mg × 0 = 0J Therefore, the work done by gravity on the given object is zero joule.

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path ob

Correct Answer - Zero Work done by the force of gravity on an object depends only on vertical displacement. Vertical displacement is given by the difference in the initial and final positions/heights of the object, which is zero Work done by gravity is given by the expression, W = mgh Where h = Vertical displacement = 0 `W = mg xx 0 = 0 J` Therefore, the work done by gravity on the given object is zero joule.

Question 2An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

The energy stored in a body by virtue of its position or configuration is called potential energy. Work done by the force of gravity on an object depends only on vertical displacement. Vertical displacement is given by the difference in the initial and final positions / heights of the object, which is zero. Work done by gravity is given by the expression, W = m g h Where, h =Vertical displacement = 0 W = m g × 0 = 0 J Therefore, the work done by gravity on the given object is zero Joule.

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

object of mass m slides down a hill of arbitrary shape An and after travelling a certain horizontal path stops because friction. The total vertical height descended is h. The friction coefficient is different for different segments for the entire path but is independent of the velocity and direction of motion. The work that a tangential force must perform to return the object to its initial position along the same path is of Two identical blocks A and B, each of mass m = 2 k g are connected to the ends of an ideal spring having force constant k = 1 0 0 0 N m − 1. System of these blocks and spring is placed on a rough floor. Coefficient of friction between blocks and floor is μ = 0 . 5. Block B is pressed towards left so that spring gets compressed. Initial minimum compression x 0 ​ of spring such that block A leaves contact with the wall when system is released is:

NCERT Solutions for Class 9 Science Chapter 11 Work and Energy

• NCERT Solutions Menu Toggle • NCERT Solutions for Class 12 • NCERT Solutions for Class 11 • NCERT Solutions for Class 10 • NCERT Solutions for Class 9 • NCERT Solutions for Class 8 • NCERT Solutions for Class 7 • NCERT Solutions for Class 6 • NCERT Books • TS Grewal Solutions • MCQ Questions Menu Toggle • NCERT MCQ These Work and Energy NCERT Solutions for Class 9 Science Chapter 11 Class 9 Scien ce Chapter 11 Work and Energy InText Questions and Answers Question 1. A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force (Fig. 11.3). Let us take it that the force acts on the object through the displacement. What is the work done in this case? Answer: When a force F acts on an object to displace it through a distance S in its direction, then the work done W on the body by the force is given by: Work done = Force x Displacement W = F × S Where, F = 7N S = 8m Therefore, work done, W = 7 × 8 = 56 Nm = 56 J Question 2. When do we say that work is done? Answer: Work is done whenever the given conditions are satisfied: • A force acts On the body. • There is a displacement of the body caused by the applied force along the direction of the applied force. Question 3. Write an expression for the work done when a force is acting on an object in the direction of its displacement. Answer: When a force F displaces a body through a distance S in the direction of the applied force, then the work done W on the body is given by the expression: Work don...

Question 2An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

The energy stored in a body by virtue of its position or configuration is called potential energy. Work done by the force of gravity on an object depends only on vertical displacement. Vertical displacement is given by the difference in the initial and final positions / heights of the object, which is zero. Work done by gravity is given by the expression, W = m g h Where, h =Vertical displacement = 0 W = m g × 0 = 0 J Therefore, the work done by gravity on the given object is zero Joule.

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

Work done by theforce of gravity on an object depends only on vertical displacement. Vertical displacement is given by the difference in the initial and final positions/heights of the object, which is zero. Work done by gravity is given by the expression, W= mg h Where, h= Vertical displacement = 0 W = mg × 0 = 0 J Therefore, the work done by gravity on the given object is zero joule.

An object thrown at a certain angle to the ground moves in a curved pa

Solution Work done by the force of gravity on an object depends only on vertical displacement vertical displacement is given by the difference in the initial and final portions/ heights of the objects, which is zero. Work done by gravity is given by the expression. w=mgh, where h = vrtical displacement = 0 w = mg × 0 = 0J Therefore, the work done by gravity on the given object is zero joule.

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