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24 m D 5 s 30 m Solution The correct option is A 4 s 20 m Given: Initial velocity, u =20 ms−1 Acceleration due to gravity, g= −10 ms−2 Upward direction is taken as positive. At maximum height, velocity will be zero, (v = 0) as the ball will change the direction of motion. Let the maximum height be H. Using third equation of motion, v2 = u2+2as



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