Class 9 maths ch 6 ex 6.2

Free PDF download of NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.2 (Ex 6.2) and all chapter exercises at one place prepared by expert teacher as per NCERT (CBSE) books guidelines. Class 9 Maths Chapter 6 Lines and Angles Exercise 6.2 Questions with Solutions to help you to revise complete Syllabus and Score More marks. Register and get all exercise NCERT Book Solutions in your emails. Download NCERT maths class 9 at Vedantu. Students can also avail of Class 9 Science from our website. Exercise: 6.2 1. In the given figure, find the values of x and y and then show that AB $\parallel $CD. (Image will be uploaded soon) Ans: Proof: It is observed that, $x + $ . 6. In the given figure, PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, the reflected ray moves along the path BC and strikes the mirror RS at C and again reflects back along CD. Prove that AB || CD. (Image will be uploaded soon) Ans: (Image will be uploaded soon) Proof: Let us draw BM $ \bot $ PQ and CN $ \bot $ RS. PQ is parallel to RS $\therefore $ BM parallel to CN BM and CN are two parallel lines and a transversal line BC cuts them at B and C respectively. $\angle MBC = \angle BCN$ (Alternate interior angles) $\angle 2 = \angle 3$ However, $\angle 1 = \angle 2$ and $\angle 3 = \angle 4$ (By laws of reflection) $\angle 1 = \angle 2 = \angle 3 = \angle 4$ Also, $\angle 1 + \angle 2 = \angle 3 + \angle 4$ $\angle ABC = \angle DCB$ However, these are alt...

Lines and Angles are discussed in Chapter 6 of CBSE Class 9. The chapter discusses crucial ideas such as the pair of angles, vertically opposite angles, and linear parity. For CBSE Class 9 Chapter 6 , Vedantu offers NCERT solutions compiled by subject-matter experts. To ace your preparations, download the Start your study process with the Vedantu experts' answers and succeed in your coursework. There are 3 exercises in NCERT Solutions for Class 9 Maths Chapter 6, which is Lines and Angles. The exercises in Chapter 6 of Class 9 Maths NCERT Solutions provide students with a comprehensive understanding of lines and angles and their applications in problem-solving. Following are the details of question types and varieties that are included in each of the exercises: • Exercise 6.1: Exercise 6.1 comprises the following types of questions: • Determining angles based on given equations • Proving equality of angles • Proving whether an angle is a straight line • Problems related to rays • Proving bisection using figures • Exercise 6.2: Exercise 6.2 has problems related to the following areas: • Proving parallelism in lines • The ratio between lines and angles • Determining the value of angles • Construction of lines • Intersection of lines • Finding interior angles in a triangle • Reflection • Mirror image • Exercise 6.3: Exercise 6.3 includes questions from the following concepts: • Determining the value of angles • Angle bisectors • Intersection of lines • Finding interior angles...

Updated for New NCERT Book - for 2023-24 Edition. Get NCERT Solutions of all exercise questions and examples of Chapter 6 Class 9 Lines and Angles free at teachoo. Answers to each question has been solved with Video. Theorem videos are also available. In this chapter, we will learn • Basic Definitions - Line, Ray, Line Segment, Angles, Types of Angles (Acute, Obtuse, Right, Straight, Reflex), Intersecting Lines, Parallel Lines • What is Linear Pair of Angles • Vertically Opposite Angles are equal • Angles formed by a transversal on parallel lines - Corresponding Angles, Alternate Interior Angles, Alternate Exterior Angles, Interior Angles on the same of transversal. And its properties • Theorem 6.6 - Lines parallel to the same line are parallel to each other • Angle Sum Property of Triangle • Exterior Angle Property of a Triangle Click on Serial Order Wise, if you want to study from the NCERT Book. This is useful when you are looking for an answer to a specific question. Or click on Concept Wise - the best way to study maths. Each chapter is divided into topics, first the topic is explained. Then, the questions of that topic, from easy to difficult. Check it out now.

Transcript Ex 6.2, 3 In the given figure, If AB || CD, EF ⊥ CD and ∠GED = 126°, find ∠AGE, ∠GEF and ∠FGE. Now, AB || CD & GE is transversal, Hence, ∠ AGE = ∠ GED ∠ AGE = 126° Now, Since AB is a line ∠ AGE + ∠ FGE = 180° 126° + ∠ FGE = 180° ∠ FGE = 180° – 126° ∠ FGE = 54° Now, ∠ GEF = ∠ GED – ∠ FED ∠ GEF = 126° – 90° ∠ FGE = 36° ∴ ∠AGE = 126°, ∠GEF = 36°, ∠FGE = 54° Show More

Board standards are built on the foundation of Class 9. Students who learn math topics and prepare well in class 9 will benefit when they graduate to class 10, where board exams will be taken. Polynomial, Chapter 6, is one such crucial chapter that serves as the foundation for the next class. A polynomial is a mathematical equation. It is made up of variables, constants, and exponents that are mixed using operations like addition, subtraction, multiplication, and division. Students will study a variety of terms by referring to Vedantu's RD Sharma Class 9 Solutions Chapter 6 - Factorization of Polynomials, including the following: • Polynomial • Degree of polynomial • Factors • Multiples • Zeros of a polynomial Vedantu provides RD Sharma Solutions for Class 9 Math Chapter 6 Factorization of Polynomials to help students improve their learning skills. Students can use RD Sharma Solutions for Class 9 to learn all of the textbook's chapters in-depth yet concise manner. Vedantu's subject matter experts have created solutions for exercise 6.2 that are one-of-a-kind for a better understanding of the topics covered. • Students can achieve their goals of achieving high marks in board exams by working on RD Sharma Solutions for Class 9. • A study guide like RD Sharma Solutions is the ideal way to strengthen the skills that are critical from an exam standpoint. • The solutions are designed in such a way that students can retain and easily remember the concepts. • The solutions have be...

Previous Next  Access NCERT Solutions for Class 6 Chapter 6: Integers Exercise 6.2 1. Using the number line, write the integer which is (a) 3 more than 5 (b) 5 more than –5 (c) 6 less than 2 (d) 3 less than –2 Solutions: (a) Hence, 8 (b) Hence, 0 (c) Hence, -4 (d) Hence, -5  2. Use a number line and add the following integers. (a) 9 + (–6) (b) 5 + (–11) (c) (–1) + (–7) (d) (–5) + 10 (e) (–1) + (–2) + (–3) (f) (–2) + 8 + (–4) Solutions: (a) Hence, 3 (b) Hence, -6 (c) Hence, -8 (d) Hence, 5 (e) Hence, -6 (f) Hence, 2 3. Add without using a number line. (a) 11 + (–7) (b) (–13) + (+18) (c) (–10) + (+19) (d) (–250) + (+150) (e) (–380) + (–270) (f) (–217) + (–100) Solutions: (a) 11 + (-7) = 4 (b) (-13) + (+18) = 5 (c) (-10) + (+19) = 9 (d) (-250) + (+150) = -100 (e) (-380) + (-270) = -650 (f) (-217) + (-100) = -317 4. Find the sum of (a) 137 and – 354 (b) – 52 and 52 (c) – 312, 39 and 192 (d) – 50, – 200 and 300 Solutions: (a) 137 and -354 (137) + (-354) = (137) + (-137) + (-217) = 0 + (-217) [(137) + (-137) = 0] = (-217) = -217 (b) -52 and 52 (-52) + (+52) = 0 [(-a) + (+a) = 0] (c) -312, 39 and 192 (-312) + (+39) + (+192) = (-231) + (-81) + (+39) + (+192) = (-231) + (-81) + (+231) = (-231) + (+231) + (-81) = 0 + (-81) [(-a) + (+a) = 0] = -81 (d) -50, -200 and 300 (-50) + (-200) + (+300) = (-50) + (-200) + (+200) + (+100) = (-50) + 0 + (+100) [(-a) + (+a) = 0] = (-50) + (+100) = (-50) + (+50) + (+50) = 0 + (+50) [(-a) + (+a) = ...