Find the perimeter of rectangle whose length is 40cm and a diagonal is 41cm

Write down the basic formula for finding the perimeter of a rectangle. This formula will help guide you as you calculate the perimeter of your own rectangle. The basic formula is: P = 2 * (l + w). X Research source • Perimeter is always the total distance around the outside edge of any shape, whether it is simple or compound. • In this equation, P stands for “perimeter,” l refers to the length of the rectangle, and w refers to the width of the rectangle. • Length always has a greater value than width. • Because opposite sides of a rectangle are equal, both lengths will be the same and both widths will be the same. This is why you write the equation as a multiplication of the sum of the length and width by 2. • You can also write the equation as P = l + l + w + w to make this very clear. Find the length and the width of your rectangle. For a basic math problem at school, the length and width of the rectangle will be provided in the problem. These are usually next to the figure of the rectangle. X Research source • If you are calculating the perimeter of a rectangle in real life, use a ruler, yardstick, or tape measure to find the length and width of the area that you are trying to measure. If you’re measuring outdoors, measure all sides to see if the opposites are truly congruent. • For example, l = 14 centimeter (5.5 in), w = 8 centimeter (3.1 in). Add the length and width. X Research source • When you are working out your perimeter equations, note that according t...

The formula for area of rectangle: Area of rectangle whose length is L and breadth is B L × B square units Area of rectangle whose diagonal is D B√(D 2 – B 2) or L√(D 2 – L 2) Click here to learn more about how to calculate the Area of Rectangle Questions with Solutions Now that we have learnt about the properties and area of rectangles, let us solve a few questions. Question 1: Calculate the area of a rectangle whose length is 28 cm and width is 34 cm. Solution: Length of the rectangle = 28 cm Width of the rectangle = 34 cm Area of the rectangle = 28 × 34 = 952 cm 2. Question 2: Calculate the area of a rectangle whose length is 30 m and width is 1200 cm. Solution: Length of the rectangle = 30 m Width of the rectangle = 1200 cm = 12 m Area of the rectangle = 30 × 12 = 360 m 2. Question 3: Calculate the area and length of the diagonal of a rectangle whose perimeter is 46 cm and length is one less than twice the width. Solution: Let the width of the rectangle be x, and then the length of the rectangle will be 2x – 1. Now, the perimeter of the rectangle = 2 × (L + B) = 46 cm ⇒ 2 × (2x – 1 + x) = 46 ⇒ 3x – 1 = 46 ÷ 2 ⇒ 3x = 23 + 1 ⇒ x = 24/3 = 8 ∴ length of the rectangle = 2x – 1 = 2(8) – 1 = 15 cm Width of the rectangle = x = 8 cm Diagonal of the rectangle = √(Length 2 + Width 2) = √(15 2 + 8 2) = √(225 + 64) = √289 = 17 cm Area of the rectangle = 15 × 8 = 120 cm 2. Question 4: Calculate the length and breadth of the rectangle whose ...

Solution: Make a rectangle ABCD having AC as one of its diagonals. Here, AB = 40 cm and AC = 41 cm BC =? By Pythagoras property, A C 2 = A B 2 + B C 2 41 2 = 40 2 + B C 2 B C 2 = 41 2 – 40 2 B C 2 = 1681 – 1600 B C 2 = 81 B C = 81 B C = 9 c m Since, the perimeter of the rectangle plot = 2 (length + breadth) Where, length = 40 cm, breadth = 9 cm Then, = 2 ( 40 + 9 ) = 2 × 49 = 98 c m