For a cell terminal potential difference is 2.2v

  1. For a cell, the terminal potential difference is 2.2V when circuit is open and reduces to 1.8V when cell is connected to a resistance R=5Ω . The internal resistance (.r.) of the cell is


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For a cell, the terminal potential difference is 2.2V when circuit is open and reduces to 1.8V when cell is connected to a resistance R=5Ω . The internal resistance (.r.) of the cell is

Solution: When circuit is open then it would be EMF of cell so E = 2.2 V When connected with an external resistance 5Ω we will measure terminal potential difference so I = R + r E ​ V A ​ − V B ​ = E − I ( r ) = I ( R ) = R + r ER ​ .....(i) So , V A ​ − V B ​ = 1.8 V o ltR = 5Ω E = 2.2 V from equation (i) 1.8 = 5 + r ( 2.2 ) ( 5 ) ​ 9 + 1.8 r = 11 1.8 r = 2 r = 18 20 ​ = 9 10 ​ Ω

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