Iupac name of k2 pdcl4

5. (a) (i) Write the IUPAC name of the following complex: [ 1 × 3 = 3 ] K 2 ​ [ PdCl 4 ​ ] (ii) Using crystal field theory, write the electronic configuration of d 5 ion, if Δ 0 ​ > P. (iii) What are Homoleptic complexes? OR (b) (i) Why chelate complexes are more stable than complexes with unidentate ligands? (ii) What is "spectrochemical series"? What is the difference between a weak Views: 5,621 A , B and C are three complexes of chromium (III) with the empirical formula H 12 ​ O 6 ​ Cl 3 ​ Cr. All the three complexes have water and chloride ion as ligands. Complex A does not react with concentrated H 2 ​ SO 4 ​ , whereas complexes B and C lose 6.75% and 13.5% of their original mass, respectively, on treatment with concentrated H 2 ​ SO 4 ​ . Identify A , B and C. 5. (a) (i) Write the IUPAC name of the following complex: [ 1 × 3 = 3 ] K 2 ​ [ PdCl 4 ​ ] (ii) Using crystal field theory, write the electronic configuration of d 5 ion, if Δ 0 ​ > P. (iii) What are Homoleptic complexes? OR (b) (i) Why chelate complexes are more stable than complexes with unidentate ligands? (ii) What is "spectrochemical series"? What is the difference between a weak Updated On Dec 22, 2022 Topic Hydrocarbons Subject Chemistry Class Class 12 Answer Type Video solution: 1 Upvotes 143 Avg. Video Duration 20 min

Chemical compound Potassium tetrachloroplatinate(II) is the 2PtCl 4. This reddish orange 4 2−. Related salts are also known including Na 2PtCl 4, which is brown-colored and soluble in alcohols, and Preparation [ ] Potassium tetrachloroplatinate is prepared by reduction of 2PtCl 4 is one of the salts that is most easily obtained from platinum 2PtCl 4 are soluble in chlorocarbons. Reactions [ ] The chloride ligands on [PtCl 4] 2− are displaced by many other 4] 2− converts to cis- PtCl 4 2− + 2 3 → cis-PtCl 2(PPh 3) 2 + 2 Cl − The anti-cancer drug PtCl 4 2− + 2 3 → cis-PtCl 2(NH 3) 2 + 2 Cl − Enedithiolates displace all four chloride ligands to give bis( Historically, an important reaction involves ammonia and [PtCl 4] 2−. This reaction affords a deep green precipitate with 2(NH 3) 2. This material, known as 4] 2− and [Pt(NH 3) 4] 2+ centres. References [ ] • ^ a b Keller, R. N.; Moeller, T. (1963). Potassium Tetrachloroplatinate(II). 9780470132333. • Elding, L. I.; Oskarsson, A.; Kukushkin, V. Yu (1997). Platinum Complexes Suitable as Precursors for Synthesis in Nonaqueous Solvents. 9780470132623. • Scott D. Cummings; Richard Eisenberg (1995). "Acid-Base Behavior of the Ground and Excited States of Platinum(II) Complexes of Quinoxaline-2,3-dithiolate". 34 (13): 3396–3403. • Ahmadi, T. S.; Wang, Z. L.; Green, T. C.; Henglein, A.; El-Sayed, M. A. (1996). "Shape-Controlled Synthesis of Colloidal Platinum Nanoparticles". 272 (5270): 1924–6. • Caseri, W. (2004). 48 (3): 91–100. •...

The IUPAC name of the complex compound [Ni(NH 3) 4][NiCl 4] is In my opinion the correct answer should be Tetrachloronickel(II) tetraamminenickelate(II), because nickel has got more oxidation number when there are chlorine atoms and therefore it should be named first. But the correct answer seems to be Tetraamminenickel(II) tetrachloronickelate(II). The coordination compound $\ce$ is tetraamminenickel(II) tetrachloridonickelate(II) or tetraamminenickel(2+) tetrachloridonickelate(2−). Note that the ligand name ‘chloro’ is obsolete. According to current IUPAC recommendations, the correct ligand name is ‘chlorido’.

hello everyone so the question is saying name of Kate pdcl4 right to be have a complex that is K2 pdcl4 pride and we have to give IUPAC name of them right here if you are observed that we have potassium we have Palladium and chlorine is there is 4th floor in it so we can write that potassium diet potassium as a alphabetical letters first so potassium and as it is folklore and right here so what it can be given it is given name Patra it Tetra chloro as a folkloric so tetrachloro chlo here in this case we can use a Florida Florida and pahle rate tight and displayed here it is having a water cans Oxidation state of plus two 10