Sin 90 value

  1. math
  2. Solve sin^2(90)
  3. Sin 1 Value
  4. Solve sin^2(90)
  5. math
  6. Sin 1 Value
  7. Sin 1 Value
  8. math
  9. Solve sin^2(90)
  10. Sin 1 Value


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the following is the code: #include //to use 'sin()' function #include int main() and I am getting this ouput: SINE TABLE : sin(0)=0.000000 sin(15)=0.650288 sin(30)=-0.988032 sin(45)=0.850904 sin(60)=-0.304811 sin(75)=-0.387782 sin(90)=0.893997 but this table is wrong when I checked it with the standard table. I want this answer: SINE TABLE : sin(0)=0.000000 sin(15)=0.258819 sin(30)=0.500000 sin(45)=0.707107 sin(60)=0.866025 sin(75)=0.965926 sin(90)=1.000000 what changes should I have to do ? C's trigonometry functions work with radians - you are using degrees. Convert your radians to degrees and you should get the results you want: i * M_PI / 180.0 On the off chance that you're running on a system where M_PI isn't defined in math.h - define it yourself: #define M_PI 3.14159265358979323846

Solve sin^2(90)

*A2A \begin

Sin 1 Value

Sin 1 The value of sin 1 is 0.8414709848, in radian. In trigonometry, the complete trigonometric functions and formulas are based on three primary ratios, i.e., sine, cosine, and tangent in trigonometry. These Let us find here how to calculate the value of sin 1. What is the Value of Sin 1? The value of sine 1 in radian is 0.8414709848. We know, π/3 = 1.047198≈1 Sin (π/3) = √3/2 and sin π = 0 Now using these data, we can write; sin1=sin[π/3−(π/3−1)] ⟹sin1=sin(π/3)cos(π/3-1)−cosπ/3sin(π/3−1) The angle π/3−1=0.047198 is a very small angle. We know that, for small angles θ, Sinθ ≈ θ and cos⁡θ ≈ 1 hence, Sin1 ≈ (√3/2×1)−[1/2×(π/3−1)] Therefore, ⟹sin1 ≈ 0.842427 How to find Sine 1 value? The sine of an angle, say x, can take either radian or degrees, as its argument. The rule is radian measurement. Now, π radian = 180 degree so, 1 rad = 180/π degree 1 rad = 57.2957795131 degree In terms of degree, we know, sin 0° = 0, sin 90° = 1 In radians, sin 0 = 0 and sin (π/2)=1 Now, π = 3.14159265359, π/2=1.5707963268 Thus, sin (1.5707963268)= 1, when the angle is in radian So, sin (1) = 0.8414709848 [when angle is in radian] sin (57.2957795131) = 0.8414709848 [when angle is in degree] Taylor’s Series to Find Sine 1 As per the \(\begin \) By solving the above, we can get; Sin 1 ≈ 0.82 What is the value of Inverse of sin 1? The inverse sin of 1, i.e., sin -1 (1) is a very unique value for the -1(x) will give us the angle whose s...

Solve sin^2(90)

*A2A \begin

math

the following is the code: #include //to use 'sin()' function #include int main() and I am getting this ouput: SINE TABLE : sin(0)=0.000000 sin(15)=0.650288 sin(30)=-0.988032 sin(45)=0.850904 sin(60)=-0.304811 sin(75)=-0.387782 sin(90)=0.893997 but this table is wrong when I checked it with the standard table. I want this answer: SINE TABLE : sin(0)=0.000000 sin(15)=0.258819 sin(30)=0.500000 sin(45)=0.707107 sin(60)=0.866025 sin(75)=0.965926 sin(90)=1.000000 what changes should I have to do ? C's trigonometry functions work with radians - you are using degrees. Convert your radians to degrees and you should get the results you want: i * M_PI / 180.0 On the off chance that you're running on a system where M_PI isn't defined in math.h - define it yourself: #define M_PI 3.14159265358979323846

Sin 1 Value

Sin 1 The value of sin 1 is 0.8414709848, in radian. In trigonometry, the complete trigonometric functions and formulas are based on three primary ratios, i.e., sine, cosine, and tangent in trigonometry. These Let us find here how to calculate the value of sin 1. What is the Value of Sin 1? The value of sine 1 in radian is 0.8414709848. We know, π/3 = 1.047198≈1 Sin (π/3) = √3/2 and sin π = 0 Now using these data, we can write; sin1=sin[π/3−(π/3−1)] ⟹sin1=sin(π/3)cos(π/3-1)−cosπ/3sin(π/3−1) The angle π/3−1=0.047198 is a very small angle. We know that, for small angles θ, Sinθ ≈ θ and cos⁡θ ≈ 1 hence, Sin1 ≈ (√3/2×1)−[1/2×(π/3−1)] Therefore, ⟹sin1 ≈ 0.842427 How to find Sine 1 value? The sine of an angle, say x, can take either radian or degrees, as its argument. The rule is radian measurement. Now, π radian = 180 degree so, 1 rad = 180/π degree 1 rad = 57.2957795131 degree In terms of degree, we know, sin 0° = 0, sin 90° = 1 In radians, sin 0 = 0 and sin (π/2)=1 Now, π = 3.14159265359, π/2=1.5707963268 Thus, sin (1.5707963268)= 1, when the angle is in radian So, sin (1) = 0.8414709848 [when angle is in radian] sin (57.2957795131) = 0.8414709848 [when angle is in degree] Taylor’s Series to Find Sine 1 As per the \(\begin \) By solving the above, we can get; Sin 1 ≈ 0.82 What is the value of Inverse of sin 1? The inverse sin of 1, i.e., sin -1 (1) is a very unique value for the -1(x) will give us the angle whose s...

Sin 1 Value

Sin 1 The value of sin 1 is 0.8414709848, in radian. In trigonometry, the complete trigonometric functions and formulas are based on three primary ratios, i.e., sine, cosine, and tangent in trigonometry. These Let us find here how to calculate the value of sin 1. What is the Value of Sin 1? The value of sine 1 in radian is 0.8414709848. We know, π/3 = 1.047198≈1 Sin (π/3) = √3/2 and sin π = 0 Now using these data, we can write; sin1=sin[π/3−(π/3−1)] ⟹sin1=sin(π/3)cos(π/3-1)−cosπ/3sin(π/3−1) The angle π/3−1=0.047198 is a very small angle. We know that, for small angles θ, Sinθ ≈ θ and cos⁡θ ≈ 1 hence, Sin1 ≈ (√3/2×1)−[1/2×(π/3−1)] Therefore, ⟹sin1 ≈ 0.842427 How to find Sine 1 value? The sine of an angle, say x, can take either radian or degrees, as its argument. The rule is radian measurement. Now, π radian = 180 degree so, 1 rad = 180/π degree 1 rad = 57.2957795131 degree In terms of degree, we know, sin 0° = 0, sin 90° = 1 In radians, sin 0 = 0 and sin (π/2)=1 Now, π = 3.14159265359, π/2=1.5707963268 Thus, sin (1.5707963268)= 1, when the angle is in radian So, sin (1) = 0.8414709848 [when angle is in radian] sin (57.2957795131) = 0.8414709848 [when angle is in degree] Taylor’s Series to Find Sine 1 As per the \(\begin \) By solving the above, we can get; Sin 1 ≈ 0.82 What is the value of Inverse of sin 1? The inverse sin of 1, i.e., sin -1 (1) is a very unique value for the -1(x) will give us the angle whose s...

math

the following is the code: #include //to use 'sin()' function #include int main() and I am getting this ouput: SINE TABLE : sin(0)=0.000000 sin(15)=0.650288 sin(30)=-0.988032 sin(45)=0.850904 sin(60)=-0.304811 sin(75)=-0.387782 sin(90)=0.893997 but this table is wrong when I checked it with the standard table. I want this answer: SINE TABLE : sin(0)=0.000000 sin(15)=0.258819 sin(30)=0.500000 sin(45)=0.707107 sin(60)=0.866025 sin(75)=0.965926 sin(90)=1.000000 what changes should I have to do ? C's trigonometry functions work with radians - you are using degrees. Convert your radians to degrees and you should get the results you want: i * M_PI / 180.0 On the off chance that you're running on a system where M_PI isn't defined in math.h - define it yourself: #define M_PI 3.14159265358979323846

Solve sin^2(90)

*A2A \begin

Sin 1 Value

Sin 1 The value of sin 1 is 0.8414709848, in radian. In trigonometry, the complete trigonometric functions and formulas are based on three primary ratios, i.e., sine, cosine, and tangent in trigonometry. These Let us find here how to calculate the value of sin 1. What is the Value of Sin 1? The value of sine 1 in radian is 0.8414709848. We know, π/3 = 1.047198≈1 Sin (π/3) = √3/2 and sin π = 0 Now using these data, we can write; sin1=sin[π/3−(π/3−1)] ⟹sin1=sin(π/3)cos(π/3-1)−cosπ/3sin(π/3−1) The angle π/3−1=0.047198 is a very small angle. We know that, for small angles θ, Sinθ ≈ θ and cos⁡θ ≈ 1 hence, Sin1 ≈ (√3/2×1)−[1/2×(π/3−1)] Therefore, ⟹sin1 ≈ 0.842427 How to find Sine 1 value? The sine of an angle, say x, can take either radian or degrees, as its argument. The rule is radian measurement. Now, π radian = 180 degree so, 1 rad = 180/π degree 1 rad = 57.2957795131 degree In terms of degree, we know, sin 0° = 0, sin 90° = 1 In radians, sin 0 = 0 and sin (π/2)=1 Now, π = 3.14159265359, π/2=1.5707963268 Thus, sin (1.5707963268)= 1, when the angle is in radian So, sin (1) = 0.8414709848 [when angle is in radian] sin (57.2957795131) = 0.8414709848 [when angle is in degree] Taylor’s Series to Find Sine 1 As per the \(\begin \) By solving the above, we can get; Sin 1 ≈ 0.82 What is the value of Inverse of sin 1? The inverse sin of 1, i.e., sin -1 (1) is a very unique value for the -1(x) will give us the angle whose s...