Three girls reshma, salma and mandip are playing a game by standing on a circle of radius 5 m drawn in a park. reshma throws a ball to salma, salma to mandip, mandip to reshma. if the distance between reshma and salma and between salma and mandip is 6 m each, what is the distance between reshma and mandip?

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawan in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawan in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip?

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Views: 5,169 ⇒ ( 20 21 ​ ) − − 800 026 ⋅ 10 ​ = 80000 02610 ​ = 8000 9261 ​ = ( 20 21 ​ ) ? n = 3 उमाही. प्रश्नमाला 22 A (1.) P के बराबर राशि पर ब्राज यह ब्याज ( P + X ) कर्ववद्धि ब्याज पर 2 वर्ष है, जो 4% प्रतिवर्ष की दर से राजि लाभ के समान लिए निवेश किया जाता है। (a) 350 (b) 240 (c) 200 (d) 280 (e) इनमें से कोई नहीं (एस.बी.आई. पी.ओ. परीक्षा, 2021) 2. एक निश्चित राशि पर 2 वर्ष के लिए 8% प्रतिवर्ष की दर से साधारण ब्याज, समान राशि पर 10% प्रतिवर्ष की दर से 2 Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Updated On Feb 22, 2023 Topic All topics Subject Mathematics Class Class 8 Answer Type Video solution: 1 Upvotes 107 Avg. Video Duration 13 min

5. Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip. Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? 6. A circular park of radius 20 m is situated in a colo David are sitting at equal distance on its boundar his hands to talk each other. Find the length of t Views: 5,752 121 b 2 − 88 b c + 16 c 2 (vii) ( l + m ) 2 − 4 l m (Hint: Expand ( l + m ) 2 first) (viii) a 4 + 2 a 2 b 2 + b 4 2. Factorise. (i) 4 p 2 − 9 q 2 (ii) 63 a 2 − 112 b 2 (iii) 49 x 2 − 36 (iv) 16 x 5 − 144 x 3 (v) ( l + m ) 2 − ( l − m ) 2 (vi) 9 x 2 y 2 − 16 (vii) ( x 2 − 2 x y + y 2 ) − z 2 (viii) 25 a 2 − 4 b 2 + 28 b c − 49 c 2 3. Factorise the expressions. (i) a x 2 + b x (ii) 7 p 2 + 21 q 2 (iii) 2 x 3 + 2 x y 2 + 2 x z 2 (iv) a m 2 + b m 2 + b n 2 + a n 2 (v) ( l m + 1 ) + m + 1 (vi) y ( y + z ) + 9 ( y + z ) (vii) 5 y 2 − 20 y − 8 z + 2 yz (viii) 10 ab + 4 a + 5 b + 2 (ix) 6 x y − 4 y + 6 − 9 x 12 × 30 0 ∘ 5. Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip. Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? 6. A circular park of radius 20 m is situated in a colo David are sitting at equal d...

Transcript Ex 9.2, 5 Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Given: Let Reshma , Salma and Mandip be donated by points R,S & M resp. Given radius = 5 m & RS = 6m, SM =6m To find: Length of RM Construction: Join OR, OS, OM Let RM intersect OS at X Solution: In ORS & OMS OR = OM OS = OS RS = SM ORS OMS ROS = MOS In ORX & OMX OR = OM ROX = MOX OX = OX ORX OMX RX = MX Since RX = MX So, OX bisects chord RM, OX RM Now, Let OX = x, So, XS = OS OX = 5 x From (3) & (4) 25 x2 = 11 x2 + 10x 25 11 x2 + x2 = 10x 14 = 10x 10x = 14 x = 14/10 x = 1.4 Putting value of x in (3) RX2 = 25 x2 RX2 = 25 (1.4)2 RX2 = 25 1.96 RX2 = 23.04 RX = ("23.04" ) RX = 4.8 Therefore, RM = 2RX = 2 4.8 = 9.6 m Distance between Reshma and Mandip is 9.6 m Show More

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6m each, what is the distance between Reshma and Mandip? Solution: Perpendicular from center to either of the chord bisects the Let O be the center of the circle, and R, M and S denote Reshma, Mandip, and Salma respectively. Draw a perpendicular OA to RS from O. Then RA = AS = 3 m. Using the We can see that quadrilateral ORSM takes the shape of a kite. (Because OR = OM and RS = SM). We know that the diagonals of a kite are perpendicular, and the main diagonal bisects the other diagonal. ∠RNS will be 90° and RN = NM Area of ∆ORS = 1/2 × RS × OA = 1/2 × 6 × 4 = 12 …(1) Also Area of ∆ORS = 1/2 × OS × RN = 1/2 × 5 × RN …(2) From equation (1) and (2) (1/2) × 5 × RN = 12 RN = 24/5 = 4.8m RM = 2 × RN = 2 × 4.8 = 9.6 m Distance between Reshma and Salma is 9.6 m. ☛ Check: Video Solution: Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6m each, what is the distance between Reshma and Mandip? Summary: If three girls Reshma, Salma, and Mandip, are playing a game by standing on a circle of radius 5mdrawn in a park, Reshma throws a ball to Salma...

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawan in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawan in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip?

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6m each, what is the distance between Reshma and Mandip? Solution: Perpendicular from center to either of the chord bisects the Let O be the center of the circle, and R, M and S denote Reshma, Mandip, and Salma respectively. Draw a perpendicular OA to RS from O. Then RA = AS = 3 m. Using the We can see that quadrilateral ORSM takes the shape of a kite. (Because OR = OM and RS = SM). We know that the diagonals of a kite are perpendicular, and the main diagonal bisects the other diagonal. ∠RNS will be 90° and RN = NM Area of ∆ORS = 1/2 × RS × OA = 1/2 × 6 × 4 = 12 …(1) Also Area of ∆ORS = 1/2 × OS × RN = 1/2 × 5 × RN …(2) From equation (1) and (2) (1/2) × 5 × RN = 12 RN = 24/5 = 4.8m RM = 2 × RN = 2 × 4.8 = 9.6 m Distance between Reshma and Salma is 9.6 m. ☛ Check: Video Solution: Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6m each, what is the distance between Reshma and Mandip? Summary: If three girls Reshma, Salma, and Mandip, are playing a game by standing on a circle of radius 5mdrawn in a park, Reshma throws a ball to Salma...

Transcript Ex 9.2, 5 Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Given: Let Reshma , Salma and Mandip be donated by points R,S & M resp. Given radius = 5 m & RS = 6m, SM =6m To find: Length of RM Construction: Join OR, OS, OM Let RM intersect OS at X Solution: In ORS & OMS OR = OM OS = OS RS = SM ORS OMS ROS = MOS In ORX & OMX OR = OM ROX = MOX OX = OX ORX OMX RX = MX Since RX = MX So, OX bisects chord RM, OX RM Now, Let OX = x, So, XS = OS OX = 5 x From (3) & (4) 25 x2 = 11 x2 + 10x 25 11 x2 + x2 = 10x 14 = 10x 10x = 14 x = 14/10 x = 1.4 Putting value of x in (3) RX2 = 25 x2 RX2 = 25 (1.4)2 RX2 = 25 1.96 RX2 = 23.04 RX = ("23.04" ) RX = 4.8 Therefore, RM = 2RX = 2 4.8 = 9.6 m Distance between Reshma and Mandip is 9.6 m Show More

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Views: 5,254 14.2 Exors then will t . Factorise the following expressions. (i) a 2 + 8 a + 16 (ii) p 2 − 10 p + 25 (iii) 25 m 2 + 30 m + 9 (Ii) 49 y 2 + 84 yz + 36 z 2 (v) 4 x 2 − 8 x + 4 (wi) 121 b 2 − 88 b c + 16 c 2 (wii) ( l + m ) 2 − 4 l m (Hint: Expand ( l + m ) 2 first) (hiii) a 4 + 2 a 2 b 2 + b 4 2. Factorise. (i) 4 p 2 − 9 q 2 (ii) 63 a 2 − 112 b 2 (iii) 49 x 2 − 36 (fiv) 16 x 5 − 144 x 3 (v) ( l + m ) 2 − ( l − m ) 2 (vi) 9 x 2 y 2 − 16 (vii) ( x 2 − 2 x y + y 2 ) − z 2 (viit) 25 a 2 − 4 b 2 + 28 b c − 49 c 2 (iii) 2 x 3 + 2 x y 2 + 2 x z 2 Views: 5,288 3 cm Q3. If A B = QR , BC = PR and C A = PQ, then (c) △ B A C ≅ △ RPQ (d) △ PQR ≅ △ BC A (a) △ A BC ≅ △ PQR (b) △ CB A E △ PRQ (c) 4 5 ∘ (d) 6 0 ∘ Q4. In figure, × ( a 2 0 ∘ (b) 3 0 ∘ Q5. In △ A BC, if A B = A C and BC is produced to D such that ∠ A C D = 10 0 ∘ then ∠ A = - (a) 2 0 ∘ (b) 4 0 ∘ (c) 6 0 ∘ (d) 8 0 ∘ Q6. If one angle of a parallelogram is 2 4 ∘ less than twice the smallest angle, then the me the largest angle of the parallelogram is (a) 17 6 0 (b) 6 8 ∘ (c) 11 2 0 (d) 10 2 ∘ Q7. The points ( − 5 , 2 ) and ( 2 , − 5 ) lie in the (a) Same quadrant (b) II and III quadrants respectively (c) II and IV ...

5. Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip. Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? 6. A circular park of radius 20 m is situated in a colo David are sitting at equal distance on its boundar his hands to talk each other. Find the length of t Views: 5,940 25 cm × 11.25 cm × 6 cm will be needed to build a bme6mx 225 cm ? 2 ∗. Find the velume of the cylinder whose base radius is 2 cm and curved surface is 28. Two tabies with top faces as two congruent trapeziums are joined as shown. The the paralle sides are 100 cm and 80 cm and the height is 45 cm. Find the top ares and the cost of polishing A at the rate of Rs. 350 per m 2. The height and crcumference of the base of a cylinder are respectively 10 cm, A lightning rod or lightning conductor is a metal rod mounted on a structure intended to protect the structure from a lightning strike. If lightning hits the it will preferentally stnke the rod and be conducted to ground through a of passing through the structure, where it could start a fire or 5. Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip. Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, wh...