Trigonometry class 10 extra questions

Free PDF Download of CBSE Class 10 Maths Chapter 9 Application of Trigonometry Multiple Choice Questions with Answers. Class 10 Maths MCQs Chapter 9 Application of Trigonometry MCQ On Application Of Trigonometry Class 10 Question 1. The shadow of a tower is equal to its height at 10-45 a.m. The sun’s altitude is (a) 30° (b) 45° (c) 60° (d) 90° Answer/ Explanation Answer: b Explaination: Reason: Let the height of tower BC = rm and sun’s altitude = θ Then Length of its shadow, AB = x m In rt. ∆ABC, tan θ = \(\frac\) = tan 30° ∴ θ = 30° Hence the Sun’s altitude is 30° MCQ Trigonometry Class 10 Question 11. The angle of elevation of top of a tower from a point on the ground, which is 30 m away from the foot of the tower is 30°. The length of the tower is (a) √3 m (b) 2√3 m (c) 5√3m (d) 10√3 m Answer/ Explanation Answer: d Explaination: MCQ Questions On Trigonometry For Class 10 Question 12. A plane is observed to be approaching the airport. It is at a distance of 12 km from the point of observation and makes an angle of elevation of 60°. The height above the ground of the plane is (a) 6√3 m (b) 4√3 m (c) 3√3 m (d) 2√3 m Answer/ Explanation Answer: a Explaination: Trigonometry Multiple Choice Questions And Answers Pdf Question 13. The upper part of a tree is broken by the wind and makes an angle of 30° with the ground. The distance from the foot of the tree to the point where the top touches the ground is 5 m. The height of the tree is (a) 10√33 m (b) 5√33 m (c) √3 m (d) √3/5 m...

This CBSE class 10 Maths practice question is from the topic Trigonometry. It tests the concept of computing trigonometric values if the sides of a right triangle are given. We will use Pythagoras Theorem to compute all sides of a right triangle. Another trigonometry extra question that helps you learn a new Pythagorean Triplet. Questions of this type are most likely to be tested as multiple choice questions in Class 10 board exam. Question 2: Given sin A = \\frac), find cos A and tan A. Explanatory Answer | Trigonometry Important Question 2 sin A = \\frac)

This page contains Important Questions for Class 10 Maths Chapter8Introduction to Trigonometry, which will help the students to prepare for the CBSE Class 10 maths Board exam 2022-23. It help the doing better in their maths paper. Extra questions of Chapter 8Introduction to Trigonometry given here which are based on the pattern of CBSE NCERT book. Students will learn about the entire syllabus and learn how to solve problems in preparation for the exams. Important Questions Class 10 Maths contains all types of questions which could be asked in the examination. We have included short answer questions as well as long answer questions for Chapter 8Introduction to Trigonometry. For more exercise, students can also refer to the Introduction to Trigonometry NCERT Solutions. Students can solve these questions and check their answers on the website. All the questions are solved in detail. 1.If sec θ + tan θ = 7, then evaluate sec θ – tan θ. Solution We know that, sec 2θ – tan 2θ = 1 ⇒ (sec θ + tan θ) (sec θ – tan θ) = 1 ⇒ (7) (sec θ – tan θ) = 1 …[sec θ + tan θ = 7] ∴ sec θ – tan θ = 1/7 2. Prove that (1+tan A - sec A) (1+tan A + sec A) = 2 tan A Solution LHS = (1+tan A) 2 - sec 2 A = 1+ tan 2 A + 2 tan A - sec 2 A = sec 2 A + 2 tan A - sec2 A = 2 tan A = RHS 3. If tan A = cot B, then find the value of (A+B) Solution We have, tan A = cot B tan A = tan(90°-B) A = 90° - B Thus, A + B = 90° 4. If sinθ + sin 2θ = 1 then prove that cos 2θ + cos 4θ = 1. Solution sinθ + sin 2θ = 1 ⇒ sinθ ...

Important Questions for Class 10 Maths Chapter 8 Introduction to Trigonometry Introduction to Trigonometry Class 10 Important Questions Very Short Answer (1 Mark) Question 1. If tan θ + cot θ = 5, find the value of tan2θ + cotθ. (2012) Solution: tan θ + cot θ = 5 … [Given tan 2θ + cot 2θ + 2 tan θ cot θ = 25 … [Squaring both sides tan 2θ + cot 2θ + 2 = 25 ∴ tan 2θ + cot 2θ = 23 Question 2. If sec 2A = cosec (A – 27°) where 2A is an acute angle, find the measure of ∠A. (2012, 2017D) Solution: sec 2A = cosec (A – 27°) cosec(90° – 2A) = cosec(A – 27°) …[∵ sec θ = cosec (90° – θ) 90° – 2A = A – 27° 90° + 27° = 2A + A ⇒ 3A = 117° ∴ ∠A = \(\frac\) = 1.41, if required) (2014OD) Solution: Filed Under:

This CBSE class 10 Maths extra question is from the chapter Introduction to Trigonometry. It tests the concept of computing angles from values of trigonometric ratios computed from the measures of the sides of a right triangle. Question 8: In a triangle ABC right angled at B, AB = 5 cm and AC = 10 cm. Determine ∠ BAC and ∠ BCA. Explanatory Answer | Trigonometry Extra Question 8 Δ ABC is right angled at B AB = 5 cm and AC = 10 cm Step 1: Calculate ∠BCA AB is the opposite side and AC is the hypotenuse to the triangle. ∴ We will use sin ∠BCA = \\frac) ∴ sin ∠BCA = sin 30° or ∠ BCA = 30° So, ∠BCA = 30° Step 2: Calculate ∠BAC In any triangle, sum of the interior angles is 180° i.e., ∠ABC + ∠BCA + ∠BAC = 180° 90° + 30° + ∠BAC = 180° ∠BAC = 60° So, ∠BAC = 60°

This CBSE class 10 Maths practice question is from the topic Trigonometry. It tests your understanding of the concepts of trigonometric ratios of a right triangle and application of Pythagoras Theorem. This extra question also helps you remember a popular Pythagorean Triplet. Question 1 : Consider right triangle ABC, right angled at B. If AC = 17 units and BC = 8 units determine all the trigonometric ratios of angle C. Explanatory Answer | Trigonometry Important Questions Q1 Given Data Length of the side BC = 8 units Length of the side AC = 17 units Step 1: Calculate the length of AB In Δ ABC, using Pythagoras theorem, AB = \\sqrt)

Important questions class 10 maths "The only way to Learn Mathematics is to Do Mathematics." - Paul Halmos 😊 Aiming to score the highest marksand top your upcoming Class 10 Board exams? We are here to help you achieve your goal! Our team of Math experts is curating sets of important questions for Class 10 Maths that you can practice with to boost your exam preparations and confidence. You can also evaluate your answers with the solutions given and rectify any errors you might have made. Our FREE CBSE Class 10 chapter-wise important questions are in the making by our experts and will be uploaded soon! Have a doubt that you want to clear? Get them clarified with simple solutions from our Math Experts at Cuemath LIVE Online Classes. Book a FREE trial class today!

Class 10 Maths Chapter 8 Introduction to Trigonometry MCQs Class 10 Maths MCQs for Chapter 8 (Introduction to trigonometry) are given here with answers and detailed explanations. All these multiple-choice questions are available online as per the CBSE syllabus (2022 – 2023) and NCERT guidelines. These MCQs for Class 10 Maths Chapter 8 are prepared as per the latest exam pattern. Solving these objective questions will help students to score better marks in the board exam. Also, download the PDF of MCQs to solve more questions on the introduction to trigonometry. Class 10 Maths MCQs for Introduction to Trigonometry Practise the MCQs for Chapter 8, introduction to the trigonometry of Class 10 Maths and verify your answers. Also, find Click here to download the PDF of additional MCQs for Practice on Introduction to Trigonometry Chapter of Class 10 Maths along with answer key: Students can also get access to Introduction to Trigonometry Class 10 Notes here. 1. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. The value of tan C is: (a) 12/7 (b) 24/7 (c) 20/7 (d) 7/24 Answer: (b) 24/7 Explanation: AB = 24 cm and BC = 7 cm tan C = Opposite side/Adjacent side tan C = 24/7 2. (Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to: (a) 0 (b) 1+2√3 (c) 1-√3 (d) 1+√3 Answer: (c) 1-√3 Explanation: sin 30° = ½, sin 60° = √3/2, cos 30° = √3/2 and cos 60° = ½ Putting these values, we get: (½+½)-(√3/2+√3/2) = 1 – [(2√3)/2] = 1 – √3 3. The value of tan 60°/co...

Trigonometry Class 10 Maths NCERT Solutions Chapter 8 is concerned with the understanding of various aspects of trigonometry. Students preparing for introduction to trigonometry class 10 will be able to clear all their concepts on trigonometry at the root level. Trigonometry is used to refine complicated problems in many physical sciences and engineering topics today. Expert faculty of Toppr produced these solutions to assist students with their first term exam preparations. It covers all major concepts in detail, allowing students to understand the ideas better. NCERT Solutions Introduction to Trigonometry, the eighth chapter of the section, concentrates on the essential concepts such as the trigonometric ratios, trigonometric identities, particular angle trigonometric ratios, and complementary angle trigonometric ratios. All of these solutions are designed with the new CBSE pattern in mind so that students have a complete understanding of their tests. Introduction to Trigonometry, Chapter 8 Questions and Answers are very useful for getting good grades in tests and properly preparing you with all of the important concepts. These NCERT Solutions are valuable tools that can assist you not only in covering the full syllabus but also in providing an in-depth analysis of the subjects. The NCERT Solutions for Class 10 Maths chapter 8 are available in pdf format below, and some of them are also included in the exercises. Given, sin A = 4 3 ​ ⇒ D C B C ​ = 4 3 ​ ⇒ B C = 3 k and A...

Class 10 Maths Chapter 8 Introduction to Trigonometry MCQs Class 10 Maths MCQs for Chapter 8 (Introduction to trigonometry) are given here with answers and detailed explanations. All these multiple-choice questions are available online as per the CBSE syllabus (2022 – 2023) and NCERT guidelines. These MCQs for Class 10 Maths Chapter 8 are prepared as per the latest exam pattern. Solving these objective questions will help students to score better marks in the board exam. Also, download the PDF of MCQs to solve more questions on the introduction to trigonometry. Class 10 Maths MCQs for Introduction to Trigonometry Practise the MCQs for Chapter 8, introduction to the trigonometry of Class 10 Maths and verify your answers. Also, find Click here to download the PDF of additional MCQs for Practice on Introduction to Trigonometry Chapter of Class 10 Maths along with answer key: Students can also get access to Introduction to Trigonometry Class 10 Notes here. 1. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. The value of tan C is: (a) 12/7 (b) 24/7 (c) 20/7 (d) 7/24 Answer: (b) 24/7 Explanation: AB = 24 cm and BC = 7 cm tan C = Opposite side/Adjacent side tan C = 24/7 2. (Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to: (a) 0 (b) 1+2√3 (c) 1-√3 (d) 1+√3 Answer: (c) 1-√3 Explanation: sin 30° = ½, sin 60° = √3/2, cos 30° = √3/2 and cos 60° = ½ Putting these values, we get: (½+½)-(√3/2+√3/2) = 1 – [(2√3)/2] = 1 – √3 3. The value of tan 60°/co...