Why does the colour of copper sulphate solution change when an iron nail is dipped in it

Copper Sulphate solution is blue . When a piece of iron nail is placed in Copper Sulphate solution, Iron Sulphate and Copper is formed as shown below Fe(s) + CuSO 4 (aq) → FeSO 4 (aq) + Cu(s) Hence, the colour of the solution turns from blue to transparent , because Fe displaces Cu from CuSO 4 (Copper Sulphate) to form FeSO 4 (Ferrous sulphate) , which is transparent.

Hello there, Here is your Answer, When an iron nail is dipped in the copper sulphate solution , the displacement reaction takes place and the iron displace the copper from the solution of copper sulphate because iron is more reactive than copper . Due to this the color of copper sulphate solution change from blue to pale green. Reaction for the solution is :- CuSO4 (aq) +Fe (s) ----> FeSO4 (aq) +Cu (s) Here Cu2+ is acts as an oxidizing agent whereas, Fe acts as reducing agent. Hope this Information will help . Thank you:) Hello aspirant, The reason behind change of colour by immersing iron nail in Copper Sulphate Solution: When an iron nail is dipped in the solution of copper sulphate solution then colour changes from blue to pale green because iron displaces copper from copper sulphate solution because iron is more reactive than copper. The iron nail becomes brownish in colour. I hope this information was helpful to you. Best of Luck!!

A single displacement reaction takes place, when an iron nail is placed in copper sulfate solution. The chemical reaction can be written as: Fe (s) + CuSO4 (aq) -> FeSO4 (aq) + Cu (s) In this case, iron, being more reactive than copper, will displace it from the solution. That is, ferrous ions or Fe(II) will go into the solution, while curic or Cu(II) will be deposited onto the nail. This cause the solution color to change from blue to green. The copper coating on the nail will give it a refdish-brown color. And we end up with solid copper and a solution of ferrous sulfate. In general, more reactive species displaces less reactive species from a solution, as shown here by displacement of copper by iron. Hope this helps. See eNotes Ad-Free

Hint:Some metals are chemically very reactive whereas other metals are less reactive or unreactive. On reaction the more reactive metal becomes a part of the salt whereas the less reactive metal is set free. Complete step by step answer: When a more reactive metal is placed in the salt solution of a less reactive metal, then the more reactive displaces (pushes out) the less reactive metal from its salt solution. These types of reactions are known as displacement reactions. General form of single displacement reaction is often of the type, \[A+BC\to B+AC\] In this reaction, element A is replaced by element B in the compound BC. When an iron nail is placed in copper sulphate (\[CuS\,\] In this case, the solution turns greenish from its original blue color due to the formation of iron sulphate. Iron lies above in the reactivity series and thus more reactive than copper. As a result, the more reactive metal (iron) displaces a less reactive metal (copper) from its salt solution (copper sulphate solution). Hence, the change in color. Note: We can also check the reactivity of a metal in reactivity series, where the metals have been arranged in a group (or series) according to their chemical reactivities. The metals which are most reactive are placed at the top whereas the least reactive metals are placed at the bottom.