Class 8 maths ch 6 ex 6.4

NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots NCERT Solutions Class 8 Maths Chapter 6 – Free PDF Download NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots are beneficial for students since it aids them in scoring high marks in the exam. The subject experts at BYJU’S outline the concepts in a distinct and well-defined manner, keeping the IQ level of students in mind. These solution modules use various shortcut hints and practical examples to explain all the exercise questions in simple and easily understandable language. Solving the Here, with the NCERT Solutions provided, the students will learn various techniques to determine whether a given natural number is a perfect square or not. The answers to all problems within this chapter present in NCERT Textbooks are provided here in a detailed and step-by-step way to help the students understand more effectively. Students can download the

NCERT Solutions for Exercise 6.4 Class 8 Maths: Class 8 students should solve NCERT Exercise questions in order to achieve high grades. They should refer to NCERT Solutions provided by Embibe for class 8 math preparation. Students who want to score well in Chapter Square and Square Roots should solve class 8 maths exercise 6.4 after reading the concepts thoroughly. Students must complete all NCERT exercises for the final exam, which is why we have produced detailed NCERT solutions for ex 6.4 class for them to refer to. They can use these NCERT solutions for exercise 6.4 Class 8 Maths anytime they run into difficulties with their studies. Continue reading this post to get the NCERT solutions for class 8 maths chapter 6 exercise 6.4. NCERT Solutions for Exercise 6.4 Class 8 Maths: Overview Before we provide the PDF link of the NCERT solution for class 8 maths chapter 6 exercise 6.4, let us first have an overview of the same: Class CBSE Class 8 Book Name NCERT Class 8 Maths Solutions NCERT Solutions for Exercise 6.4 Maths Available on Embibe Price Free NCERT Solutions for Exercise 6.4 Class 8 Maths: Download PDF Here we have provided the class 8 maths exercise 6.4 solutions PDF. Just click on the link and download the PDF: NCERT Solutions for ex 6.4 class 8 Square and Square Roots: Chapter Description Square numbers include integers like 1, 4, 16, and 36. M is the square number if it can be stated as n2 where n is also a natural integer. • This chapter explains the properties...

CBSE Solutions | Maths Class 8 Cbse Syllabus based NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ncert book solutions are available here. These Ncert book chapter wise questions and answers are very helpful for Cbse board exam. Cbse recommends Ncert books and most of the questions in Cbse exam are asked from Ncert textbooks. Class 8 Maths chapter wise Ncert Solution for Maths all chapters can be download from our website NCERT | Class 8 Maths NCERT Solutions Class 8 Maths Book: National Council of Educational Research and Training (NCERT) Board: Central Board of Secondary Education (CBSE) Class: 8th Subject: Maths Chapter: 6 Chapters Name: Squares and Square Roots Medium: English Squares and Square Roots | Class 8 Maths | NCERT Books Solutions You can refer to Squares and Square Roots to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams. NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Exercise 6.1 Ex 6.1 Class 8 Maths Question 1. What will be the unit digit of the squares of the following numbers? (i) 81 (ii) 272 (iii) 799 (iv) 3853 (v) 1234 (vi) 26387 (vii) 52698 (viii) 99880 (ix) 12796 (x) 55555 Solution: The unit digit of the squares of the given numbers is shown against the numbers in the following table : Ex 6.1 Class 8 Maths Question 2. The following numbers are not perfect squares. Give reason, (i) 1057 (ii) 23453 (iii) 7928 (iv) 222222 (v) 64000 (vi) 89722 ...

• • • Board CBSE Textbook NCERT Class Class 8 Subject Maths Chapter Chapter 6 Chapter Name Squares and Square Roots Exercise Ex 6.4 Number of Questions Solved 9 Category NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.4 Question 1. Find the square root of each of the following numbers by Division method: Solution. (i) 2304 (ii) 4489 (iii) 3481 (iv) 529 (v) 3249 (vi) 1369 (vii) 5776 (viii) 7921 (ix) 576 (x) 1024 (xi) 3136 (xii) 900 Question 2. Find the number of digits in the square root of each of the following numbers (without any calculation): (i) 64 (ii) 144 (iii) 4489 (iv) 27225 (v) 390625. Solution. (i) 64 Number (n) of digits in 64 = 2 which is even. ∴ Number of digits in the square root of 64 \(\frac \) ∴ Length of the side of the square Question 7. In a right triangle ABC, ∠B = 90°. (a) If AB = 6 cm, BC = 8 cm, find AC (b) If AC 13 cm, BC = 5 cm, find AB. Solution. (a) In the right triangle ABC, ∠B = 90° Given Question 8. A gardener has 1000 plants. He wants to plant these in such a way that the number of rows and the number of columns remain same. Find the minimum number of plants he needs more for this. Solution. Let the number of rows be x. Then the number of columns is x. Question 9. There are 500 children in a school. For a P.T. drill they have to stand in such a manner that the number of rows is equal to number of columns. How many children would be left out in this arrangement? Solution. Let the number of rows be x. Then the number ...

ML Aggarwal CBSE Solutions Class 8 Math 6th Chapter Percentage and its Applications Exercise 6.4 (1) (i) CP = 50/- GST = 5% of 50 ∴ = 5/100 X50 = 5/2 /- ∴ SP = 50 + 5/2 = 100+5/2 = 105/2 = 50.50/- (Ans) (ii) 1kg = 150/- ∴ CP of 5kg = 150X5 = 750/- ∴ GST = 5% of CP = 5/100 X750 = 37.5/- ∴ SP = 750 + 37.5 = 787.50/- (Ans) (2) (i) Let , original price = x ∴ GST = 8% of x = 8x/100 = 2x/25 According to question – X + 2x/25 = 13500 Or, 25x + 2x/25 = 13500 Or, 27x/25 = 13500 Or, x = 13500X25/27 Or, x = 12500 ∴ Original price = 12500/- (ii) Let, original price = x ∴ GST = 8% x = 8x/10 = 2x/25 According to question – X + 2x/25 = 180 Or, 25x + 2x/25 = 180 Or, 27x = 180 X 25 Or, x = 180X25/27 = 500/3 = 166.66/- (3) SP = 34992 Let, CP = x ∴ GST = 8% of x = 8x/100 = 2x/25 According to question – X + 2x/25 = 34992 Or, 25x + 2x/25 = 34992 Or, 27x = 34992 X 25 Or, x = 34992 X 25/37 = 32,400 ∴ CP = 32,400 /- (Ans) (4) SP = 1296/- Original price = 1200/- Let, GST = x% of 1200 = x/100 X1200 = 12x According to question – 1200 + 12x = 1296 Or, 12x = 1296 – 1200 = 96 Or, x = 96/12 = 8 ∴ GST = 8% (Ans) (5) Let, CP = x GST 1 = 8% of x = 8x/100 = 2x/25 Old SP = 523.80 According to qne – X + 2x/25 = 523.80 Or, 25x + 2x/25 = 523.80 Or, 27x = 523.80 X 25 Or, x = 523.50 X 25/27 = 485 ∴ CP = 485/- Now, GST 2 = 10% of 485 = 10/100 X485 ∴ Now SP = 485 + 48.50 = 533.50/- (Ans) (6) MP = 4800/- Dis = 10% ∴ SP = 4800 X 90/100 = 4320/- GST = 8% of SP = 8/100 X 4320 = 345.6/- ∴ The paid amount = 4320 + 345.6 =...

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