Class 7 maths chapter 11 exercise 11.4 solutions

In 7 Maths Chapter 11 Exponents and Powers, we will learn about the various rules exponents and conversion of powers into exponent and exponents to powers. In this topic of Note: In most of the questions that are taken in Chapter 11, the base of a power was taken an integer. But all the results of this chapter apply equally well to a base which is a rational number. Standard Form: Any number can be The questions based on, conversing of number into standard form or Scientific form to normal form and vice versa are given in the last exercise, are very important for the further classes. Most of the larger numbers are normally written in the standard form.

• • • • Board CBSE Textbook NCERT Class Class 7 Subject Maths Chapter Chapter 11 Chapter Name Perimeter and Area Exercise Ex 11.4 Number of Questions Solved 11 Category NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 Question 1. A garden is 90 m long and 75 m broad. A path 5 m wide is to be built outside and around it. Find the area of the path. Also, find the area of the garden in a hectare. Solution: Question 2. A 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path. Solution: PQ = 125 m + 3m + 3m = 131 m QR = 65m + 3m + 3m = 71 m Question 3. A picture is painted on a cardboard 8 cm long and 5 cm wide such that there is a margin of 1.5 cm along each of its sides. Find the total area of the margin. Solution: Question 4. A verandah of width 2.25 m is constructed all along the outside of a room which is 5.5 m long and 4 m wide. Find: (i) the area of the verandah (ii) the cost of cementing the floor of the verandah at the rate of ₹200 per m 2. Solution: Question 5. A path 1 rn wide is built along the border and inside a square garden of side 30 m. Find. (i) the area of the path. (ii) the cost of planting grass in the remaining portion of the garden at the rate of f 40 per m 2. Solution: Question 6. Two crossroads, each of width 10 m, cut at right angles through the centre of a rectangular park of the length 700 m and the breadth 300 m parallel to its sides. Find the area of the roads. Als...

Chapter 11: Percentage Exercise – 11.4 Question: 1 Find each of the following: (i) 7% of Rs.7150 (ii) 40% of 400Kg (iii) 20% of 15.125litres (iv) 3(1/3)%of 90 km (v) 2.5% of 600metres Solution: Question: 2 Find the number whose 12(1/2) % is 64. Solution: Question: 3 What is the number, 6(1/4)%of which is 2? Solution: Question: 4 If 6 is 50% of a number, what is the number? Solution:

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 • • • • NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.2 Ex 11.2 Class 7 Maths Question 1. Find the area of each of the following parallelograms: Solution: (a) Area of the parallelogram = base × altitude = 7 cm × 4 cm = 28 cm 2 (b) Area of the parallelogram = base × altitude = 5 cm × 3 cm = 15 cm 2 (c) Area of the parallelogram = base × altitude = 2.5 cm × 3.5 cm = 8.75 cm 2 (d) Area of the parallelogram = base × altitude = 5 cm × 4.8 cm = 24.0 cm 2 (e) Area of the parallelogram = base × altitude = 2 cm × 4.4 cm = 8.8 cm 2 Ex 11.2 Class 7 Maths Question 2. Find the area of each of the following triangles: Solution: Area of the triangle = \(\frac\) × base × height Filed Under: Tagged With:

NCERT Solutions for Class 7 Maths Exercise 11.4 Chapter 11 Perimeter and Area * According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 9. NCERT Solutions for Class 7 Maths Exercise 11.4 Chapter 11 Perimeter and Area in simple PDF are available here. Conversion of units and applications are the topics covered in this exercise of Download PDF carouselExampleControls112 Previous Next Access Other Exercises of NCERT Solutions for Class 7 Maths Chapter 11 – Perimeter and Area Access Answers to NCERT Solutions Class 7 Maths Chapter 11 – Perimeter and Area Exercise 11.4 1. A garden is 90 m long and 75 m broad. A path 5 m wide is to be built outside and around it. Find the area of the path. Also find the area of the garden in hectare. Solution:- From the question it is given that, Length of the garden (L) = 90 m Breadth of the garden (B) = 75 m Then, Area of the garden = length × breadth = 90 × 75 = 6750 m 2 From the figure, The new length and breadth of the garden when path is included is 100 m and 85 m, respectively. New area of the garden = 100 × 85 = 8500 m 2 The area of path = New area of the garden including path – Area of garden = 8500 – 6750 = 1750 m 2 For 1 hectare = 10000 m 2 Hence, area of garden in hectare = 6750/10000 = 0.675 hectare 2. A 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path. Solution:- From the question it is given that, Length of the park (L) = 125...

Chapter 11 Perimeter and Area Exercise 11.4 Class 7 Maths NCERT Solutions which will be useful inin scoring good marks in the examinations.These NCERT Solutions are prepared as per the accordance of latest CBSE guidelines so you can score maximum marks.Class 7 NCERT Solutions will help students in developing their understanding of the chapter and obtain maximum marks in the exams.

Class 7 Maths NCERT Solutions Chapter 11 – Perimeter and Area comprises of the 4 Exercises • • • • This Chapter contains the Exercises relating to the following topics , which are discussed in Chapter 11 – Perimeter and Area Class 7 NCERT book : – • 11.1 INTRODUCTION • 11.2 SQUARES AND RECTANGLES • 11.2.1 Triangles as Parts of Rectangles • 11.2.2 Generalising for other Congruent Parts of Rectangles • 11.3 AREA OF A PARALLELOGRAM • 11.4 AREA OF A TRIANGLE • 11.5 CIRCLES • 11.5.1 Circumference of a Circle • 11.5.2 Area of Circle • 11.6 CONVERSION OF UNITS • 11.7 APPLICATIONS NCERT Solutions for Class 7 Maths Chapter 11 Exercise 11.1 1. The length and the breadth of a rectangular piece of land are 500 m and 300 m respectively. Find i. Its area ii. The cost of the land, if 1 m 2 of the land costs Rs. 10,000. Solution: i. Length = 500 m Breadth = 300 m Area of rectangular piece of land = length × breadth = 500 × 300 = 150000 m 2 ii. Cost of 1 m 2 of land = Rs. 10,000 Cost of 150000 m 2 of land = Rs. 10,000 × 150000 = Rs. 1500000000 2. Find the area of a square park whose perimeter is 320 m. Solution: Let the side of the square be s Perimeter of the square = 320 m 4s = 320 m s = 80 m Area of the square = (side) 2 = s 2 = 80 2 = 6400 m 2 3. Find the breadth of a rectangular plot of land, if its area is 440 m 2 and the length is 22 m. Also find its perimeter. Solution: Let the breadth of the rectangle be b Length of the rectangle = 22 m Area of the rectangle = 440 m 2 Length × Bre...