Chloro and bromobenzene reacted with the very strong base sodium amide (NaNH 2 at low temperature (-33 ºC in liquid ammonia) to give good yields of aniline (aminobenzene). However, ortho-chloroanisole gave exclusively meta-methoxyaniline under the same conditions. These reactions are described by the following equations.

Aniline is obtained by fresh distillation of the obtained mixture. To make aniline in the laboratory, take 25 grams of nitrobenzene and 50 grams of granulated tin in a round flask. A vertical air condenser is to be placed in the flask. Add 110 ml of concentrated hydrochloric acid little by little to the flask.

Solution Solve with us Step 1 Primary amines undergo treatment with chloroform and ethanolic potassium hydroxide to yield isocyanides. The reaction is known as Carbylamine reaction. This reaction is a test for primary amines. Secondary and tertiary amines do not respond to this test.

In acid, the nitrogen gets protonated making the chloride (if using hydrochloric acid) salt of aniline, which is soluble. In a basic solution, the nitrogen is not protonated, so the solubility is.

Now, why is 2-methoxyaniline more basic than 3-methoxyaniline (even though 2-methoxyaniline has reduction of basicity due to ortho -effect but 3-methoxyaniline does not)? Also what would be the correct order of basicity if nitro group was present in place of methoxy group? Would ortho -effect still take place? organic-chemistry acid-base

Pt/CeO2 catalysts with different support shapes and prereduction temperatures were prepared and tested in the liquid-phase hydrogenation of nitrobenzene. Detailed characterizations reveal that the support shape effect of Pt/CeO2 catalysts on nitrobenzene hydrogenation originates from the exposed crystal planes on CeO2 with different reducibilities. A high-energy surface is readily reduced to.

Complete answer: The structure of aniline contains an ammonia group + dilute HCl → C l − attached to the benzene ring. Due to the presence of a lone pair of nitrogen atoms of the ammonia group of the aniline, due to which it acts as a nucleophile. It’s ability to donate the lone pair of electrons to an electrophilic center makes it basic in nature.

An alternative version of the well-known demonstration carbon snake (the dehydration reaction of sugar by concentrated sulfuric acid forming a column of graphite) consists in mixing paranitroaniline and sulfuric acid. This reaction is very vigorous and occurs suddenly, forming a similar column of black solid.

Give reason : pKb of aniline is more than that of methylamine amines cbse class-12 1 Answer +1 vote answered Jan 12, 2019 by Amoli (50.5k points) selected Jan 12, 2019 by faiz Best answer Aniline undergoes resonance and as a result, the electrons on the N-atom are delocalized over thebenzene ring.

Which of the following conditions will allow for the reduction of a nitrobenzene to aniline? (Select all that are possible) HCl, Fe Br2, FeBr3 H2, Pt H2 This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer

Give reasons of the following observations: a. Aniline is acetylated before nitration reaction. b. pKb of aniline is lower than the m-nitroaniline.

Nitration of aniline in strong acidic medium also gives m-nitroaniline because: 1.In spite of substituents nitro group always goes to only m-position2.In electrophilic substitution reactions amino group is meta directive3.In absence of substituents nitro group always goes to only m-position4.In acidic (strong) medium aniline is present as anili.